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spayn [35]
3 years ago
11

What happens to the electric field around a single charge when another charge is added to the system?

Physics
2 answers:
liberstina [14]3 years ago
4 0
THE electric field of the previously present electric charge,now produces the exact same value of electric field irrespective of the other charge added.but this time the net field will be different as it involves the vectorial addition of electric field
yKpoI14uk [10]3 years ago
4 0

The correct answer to the question is : The net electric field will be modified, and they may repel or attract depending on the nature of charges.

EXPLANATION:

As per the question, initially there was a single isolated charge. The field produced by the charge may be directed towards the charge or away from it depending on the nature of charge.

When another charge is added to the system, the electric field produced by the former one will be modified. If the two charges are of same nature, then they will apply tangential pressure on each. If they are of opposite nature, they will apply longitudinal contraction on each other.

We know that electric field is a vector quantity. Hence, the net electric field at a point in the electric field will be obtained by the vector addition of individual charges.

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A train traveling at 25 m/s is blowing its whistle at 440 Hz as it crosses a level crossing. You are waiting at the crossing and
ohaa [14]

Answer:

b) 472HZ, 408HZ

Explanation:

To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

f_o=f\frac{v_s+v_o}{v_s-v}\\\\f_o=f'\frac{v_s-v_o}{v_s+v}\\\\

fo: frequency of the source = 440Hz

vs: speed of sound = 343m/s

vo: speed of the observer = 0m/s (at rest)

v: sped of the train

f: frequency perceived when the train leaves us.

f': frequency when the train is getTing closer.

Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

f=f_o\frac{v_s-v}{v_s+v_o}=(440Hz)\frac{340m/s-25m/s}{340m/s}=408Hz\\\\f'=f_o\frac{v_s+v}{v_s-v_o}=(440Hz)\frac{340m/s+25m/s}{340m/s}=472Hz

hence, the frequencies for before and after tha train has past are

b) 472HZ, 408HZ

6 0
3 years ago
We have two solenoids: solenoid 2 has twice the diameter, half the length, and twice as many turns as solenoid 1. The current in
leva [86]

Answer:

the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.

Explanation:

Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:

B=\mu_0\, \frac{N}{L} I

Then, if we assign the subindex "1" to the quantities that define the magnetic field (B_1) inside solenoid 1, we have:

B_1=\mu_0\, \frac{N_1}{L_1} I_1

notice that there is no dependence on the diameter of the solenoid for this formula.

Now, if we write a similar formula for solenoid 2, given that it has :

1) half the length of solenoid 1 . Then L_2=L_1/2

2) twice as many turns as solenoid 1. Then N_2=2\,N_1

3) three times the current of solenoid 1. Then I_2=3\,I_1

we obtain:

B_2=\mu_0\, \frac{N_2}{L_2} I_2\\B_2=\mu_0\, \frac{2\,N_1}{L_1/2} 3\,I_1\\B_2=\mu_0\, 12\,\frac{N_1}{L_1} I_1\\B_2=12\,B_1

5 0
3 years ago
How many days are in a year on mars
Triss [41]
687 days
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7 0
3 years ago
How do you label <br> Time= energy • power
Lana71 [14]

First of all, that equation is not correct, which may be the reason
that you're having trouble assigning units to the quantities.

Power is defined as [energy / time],  so  [Energy] = [ power x time ],
and
         [Time] = [ energy / power ].

Unit-wise, these equations are correct just as they appear here,
with no proportionality constants or conversion factors, when ...

[ Power ] = watts
[ Energy ] = joules
[ Time ] = seconds .
 

5 0
2 years ago
The real advantage to hydrostatic weighing is that it __________.
Molodets [167]

Answer:

B. gives one of the most accurate measurements of body fat

5 0
3 years ago
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