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3 years ago

What happens to the electric field around a single charge when another charge is added to the system?

2 answers:

4 0

THE electric field of the previously present electric charge,now produces the exact same value of electric field irrespective of the other charge added.but this time the net field will be different as it involves the vectorial addition of electric field

yKpoI14uk [10]3 years ago

4 0

The correct answer to the question is : The net electric field will be modified, and they may repel or attract depending on the nature of charges.

EXPLANATION:

As per the question, initially there was a single isolated charge. The field produced by the charge may be directed towards the charge or away from it depending on the nature of charge.

When another charge is added to the system, the electric field produced by the former one will be modified. If the two charges are of same nature, then they will apply tangential pressure on each. If they are of opposite nature, they will apply longitudinal contraction on each other.

We know that electric field is a vector quantity. Hence, the net electric field at a point in the electric field will be obtained by the vector addition of individual charges.

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2 years ago

One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large

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The correct answer is "6666.67 N".

Explanation:

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3 years ago

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3 years ago

A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc

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The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

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Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

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