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3 years ago

What happens to the electric field around a single charge when another charge is added to the system?

2 answers:

4 0

THE electric field of the previously present electric charge,now produces the exact same value of electric field irrespective of the other charge added.but this time the net field will be different as it involves the vectorial addition of electric field

yKpoI14uk [10]3 years ago

4 0

The correct answer to the question is : The net electric field will be modified, and they may repel or attract depending on the nature of charges.

EXPLANATION:

As per the question, initially there was a single isolated charge. The field produced by the charge may be directed towards the charge or away from it depending on the nature of charge.

When another charge is added to the system, the electric field produced by the former one will be modified. If the two charges are of same nature, then they will apply tangential pressure on each. If they are of opposite nature, they will apply longitudinal contraction on each other.

We know that electric field is a vector quantity. Hence, the net electric field at a point in the electric field will be obtained by the vector addition of individual charges.

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1. What happens to particle spacing when temperature increase, What we call this process?

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Answer:

Particle spacing increases and it's called evaporating

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4 years ago

A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de

oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

$\eta = \frac{W}{Q_{in}}$

where

W is the useful work done by the engine

$Q_{in}$ is the heat in input to the machine

In this problem, we have:

$Q_{in}=600 kJ$ is the heat absorbed

$W=600 kJ-175 kJ=425 kJ$ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

$\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%$

(a) $737^{\circ}C$

The efficiency of an engine can also be rewritten as

$\eta = 1-\frac{T_C}{T_H}$

where

$T_C$ is the absolute temperature of the cold sink

$T_H$ is the temperature of the source

In this problem, the temperature of the sink is

$T_C = 20^{\circ}C + 273=293 K$

So we can re-arrange the equation to find the temperature of the source:

$T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C$

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3 years ago

Calculate the answer to the correct number of significant digits 0.055 * 5.1 =

I am Lyosha [343]

Answer:

0.055 * 5.1 = 0.2805

Explanation:

I used a calculator so it should be accurate! yw!! :D

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3 years ago

The periodic table is an arrangment of the chemical elements, ordered by atomic number, into families, and by doing so illustrat

olya-2409 [2.1K]

Answer:

Option B) reactive to nonreactive

Explanation:

A) Solid to gas

This might apply, because most of the gases are to the right portion of the periodic table

There are just a few elements that are gases at room temperature; a total of 11: six noble gases (group 18), two halogens (group 17), oxygen (group 16), nitrogen (group 15), and hydrogen (group 1).

Hydrogen is an exception to this trend because they are in the left part of the periodic table.

B) Reactive to nonreactive

The most reactive metals are in group 1 (alkali metals) and the most reactive nonmentals are in the group 18 (halogens). Hence, it is false that the from left to right the preperties go from reactive to nonreactive.

Hence, this is the one that cannot apply.

C) Metal to metalloid to nonmetal

It is true that the metallic character of the elements decreases from left to right; the metals are to the left, going to the right you find some metalloids, and further to the right you find the nonmetals.

Hence, this trend is correct.

D) Increasing number of outer-shell electrons

The number of outer-shell electrons definetly increase from left to right.

The number of electrons in neutral atoms equals the number of protons (to balance the positive and negative charges). Since, the atomic number (the number of protons) increase from left to right, the number of electrons also increase.

In a period (a row of the periodic table) the electrons add to the same outer-shell, then you will find that the number of electrons of the outer-shell increase from left to right. Hence, this is also a correct trend.

In conclusion, the only trend that does not apply is the described by the option B).

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3 years ago

Read 2 more answers

WASSCE

Ratling [72]

Answer:

i think the answer is letter c

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3 years ago