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svlad2 [7]
3 years ago
7

Punkt p (1;2k+1) należy do wykresu funkcji f(x)=-4x2+7. Oblicz k

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

k = 1

Step-by-step explanation:

English Translation

Find k if the point P (-1, 2k + 1) belongs to the graph of the function f (x) = - 4x^2 + 7.

The function is given as

y = f(x) = -4x² + 7

and point (-1, 2k+1) lies on the graph.

This point means that, at x = -1, y = 2k+1

y = -4x² + 7

Substituting the values in

2k + 1 = -4(-1)² + 7

2k + 1 = -4 + 7 = 3

2k = 3 - 1

2k = 2

k = 1

Hence, the point (-1, 2k+1) is (-1, 3)

To check,

y = -4x² + 7

3 = -4(-1)² + 7

3 = -4 + 7

3 = 3

So, this is truly correct.

Hope this Helps!!!

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Step 1: Simplify both sides of the equation.

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(−4)(x)+(−4)(3)=8(Distribute)

−4x+−12=8

−4x−12=8

Step 2: Add 12 to both sides.

−4x−12+12=8+12

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Step 3: Divide both sides by -4.

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3 years ago
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(Check your work)

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8 0
2 years ago
I need help with 1-3 i don’t understand that problems and its already over due
Nina [5.8K]

Step-by-step explanation:

For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).

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The maximum width is 22 feet.

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