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Dima020 [189]
3 years ago
12

What point is symmetric to (2,7) on this quadratic graph? (2,-1) (-5,0) (-2,4) (-6,7)

Mathematics
1 answer:
mariarad [96]3 years ago
4 0

Answer:

(-6,7)

Step-by-step explanation:

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Please help me i’m stuck !
Savatey [412]

Answer:

1n plus 2d

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3 0
3 years ago
A recipe calls for 2 teaspoons of orange juice. A can of orange juice is 22 fluid ounces. How many teaspoons of juice are in a c
Dmitrij [34]

Answer:

132 teaspoons in a 22 ounce can

Step-by-step explanation:

There are 6 teaspoons in 1 ounce

22 * 6 = 132

5 0
3 years ago
Suppose the equation for line A is given by 2x = 5y – 25. If line A and B are perpendicular
Ludmilka [50]

The required equation of line B is 2y+5x=-2

The equation of a line in point-slope form is expressed as:

y-y0 = m(x-x0)

m is the slope of the line

(x0, y0) is the point on the line

Given the line A expressed as:

2x = 5y – 25

Rewrite in standard form

5y = 2x + 25

y = 2/5 x + 5

The slope will be 2/5

The slope of the perpendicular line will be;

M = \frac{-1}{(2/5)}\\M = \frac{-5}{2}

Substitute the point (-6, 14) and slope -5/2 into the equation above to get the required equation of line B

y-14=-5/2(x+6)\\2(y-14) = -5(x+6)\\2y-28=-5x-30\\2y+5x=-30+28\\2y+5x=-2\\

Hence the required equation of line B is 2y+5x=-2

Learn more here: brainly.com/question/13140886

6 0
3 years ago
I don't understand how to find a. Please help!
Rama09 [41]
The small right angled triangle with hypotenuse vale 5 is similar to the big triangle with b as the hypotenuse
Corresponding sides are in the same ratio so we can write 
a/12 = 5/b.....(1)

Also  applying pythagoras theorem to the large triangle 
b^2 = 5^2 + 12^2
b^2 = 169
b = 13

So substituting in equation (1):-
a  / 12 = 5  / 13
a = (5*12 ) / 13

8 0
3 years ago
Read 2 more answers
What is the solution for the system of equations?<br><br> -4x+y=-2<br> y+5=-6x
Aliun [14]

Answer:

(-3/10,-16/5)

Step-by-step explanation:

One way to solve a system of equations is by elimination.  We can take one equation and subtract the other equation from it to cancel out on of the variables making the equation into something we can solve.  In this case the Y's will cancel out because we have 1 Y in each equation

-4x+y=-2

6x+y=-5 subtract

-4x-6x=-10x

y-y=0

-2-(-5)=3

so our equation is -10x=3 and we can solve for x giving us x=-3/10

now we can plug -3/10 in for x into either of the original equations and solve for Y

y+5=-6(-3/10)

y+5=9/5

y=-16/5

so our answer is (-3/10,-16/5)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

6 0
3 years ago
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