What does five over 3 times five 5/3 equal?

Anna [14]

1.0210 is the answer

hoped this helped

5 0

2 years ago

A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a populat

eimsori [14]

Answer:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

$p_v =P(t_{15}>2)=0.0320$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

Step-by-step explanation:

1) Data given and notation

$\bar X=25$ represent the sample mean

$s=2$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =24$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Confidence =0.95 or 95%

$\alpha=0.05$

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is higher than 24, the system of hypothesis would be:

Null hypothesis: $\mu \leq 24$

Alternative hypothesis: $\mu > 24$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>2)=0.0320$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

3 0

2 years ago

What equation results from completing the squre and then factoring x^2+10=15

nlexa [21]

For this case we must complete squares:

$x ^ 2 + 10x = 15$

We add the square of half the coefficient of the term "x",

$(\frac {b} {2a}) ^ 2$ on both sides of the equation:

$x^2+10x+(\frac {10} {2 (1)}) ^ 2 = 25 + 15\\x ^ 2 + 10x + 5 ^ 2 = 25 + 15$

According to the perfect square trinomial we have:

$(a + b) ^ 2 = a ^2 + 2ab + b ^ 2$

Rewriting the expression we have:

$a = x\\b = 5\\(x + 5) ^ 2 = 25 + 15\\(x + 5) ^ 2 = 40$

ANswer:

$(x + 5) ^ 2 = 40$

6 0

2 years ago

(100+ POINTS)

horsena [70]

Answer:

1) 102.7 meters

2) 11

Step-by-step explanation:

1) -4.9x² + 75x = -4.9x² + 50x + 38

25x = 38

x = 1.52 s

Height = -4.9(1.52)² + 75(1.52) = 102.67904 m = 102.7 m

2) f(x) = x² + 3x - 2

f(2) = 2² + 3(2) - 2 = 8

f(6) = 6² + 3(6) - 2 = 52

Average rate of change:

(52-8)/(6-2) = 11

5 0

2 years ago

Read 2 more answers

Identify the horizontal asymptote of f(x)=x^2+6x-9 over x-2

lora16 [44]

$\bf \cfrac{x^2+6x-9}{x-2}\qquad 
\begin{cases}
x^2\impliedby \textit{has a degree of 2}\\
x^1\impliedby \textit{has a degree of 1}
\end{cases}$

if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.

7 0

2 years ago