You first subtract the speed at which the man is moving (11 m/s) from the rate the boat is moving (12.4 m/s). Which equals 1.4, then divide it by 6 meters, as the man is moving relative to the boat.
It therefore equals 4.29 s
E = q/r^2
where r is perpendicular distance between the point and source charge
Ex = E cos theta
Ey = E sin theta
take theta angle between horizontal and line joining the point charge and the point
Answer:
E_Phase = 560V
Explanation:
The computation of the voltage i.e. dropped across each phase is shown below:
Given that
The delta connection line voltage is
E_line = 560 V
And, in the case of delta connection, the line voltage would be equivalent to the phase voltage
That means
E_Phase = E_Line
= 560 V
Hence, the voltage i.e. dropped across each phase is
E_Phase = 560V
Temperature probe
The difference in temperature is needed for this experiment.