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Bingel [31]
3 years ago
12

Una ardilla corre desarrollando una aceleracion de 3.5 m/s2 la fuerza ejecidas por las patas traseras es de 5 N. Cual sera la ma

sa de la ardilla?
Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

1.43 kg

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force on an object

m is its mass

a is its acceleration

For the squirrel in the problem, we have:

a=3.5 m/s^2 is the acceleration

F = 5 N is the net force acting on it

Solving for m, we find its mass:

m=\frac{F}{a}=\frac{5}{3.5}=1.43 kg

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For a car of weight 9000 N the recommended tyre pressure is 18 N/cm².Find
GarryVolchara [31]

<em>math</em><em>ematically</em><em>,</em>

<em>pressure =  \frac{force}{area}</em>

<em>but</em><em> </em><em>weigh</em><em>t</em><em>=</em><em> </em><em>Force</em><em>.</em>

given pressure

18N/cm^2

and <em>Force</em> = 9000N

making <em>area</em> the subject in the relation above.

Area =  \frac{force}{pressure}

substitute their values into the equation

Area =  \frac{9000}{18}

Area = 500 {cm}^{2}

3 0
3 years ago
Find the density of a planet with a radius of 8000 m if the gravitational acceleration for the planet, gp, has the same magnitud
Naya [18.7K]

Answer:

Density = 3 x 10⁻⁵ kg/m³

Explanation:

First, we will find the volume of the planet:

V = \frac{4}{3}\pi r^3\ (radius\ of\ sphere)\\\\V =   \frac{4}{3}\pi (8000\ m)^3\\\\V = 2.14\ x\ 10^{12}\ m^3

Now, we will use the expression for gravitational force to find the mass of the planet:

g = \frac{Gm}{r^2}\\\\m = \frac{gr^2}{G}

where,

m = mass = ?

g = acceleration due to gravity = 6.67 x 10⁻¹¹ m/s²

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

r = radius = 8000 m

Therefore,

m = \frac{(6.67\ x\ 10^{-11}\ m/s^2)(8000\ m)^2}{6.67\ x\ 10^{-11}\ Nm^/kg^2}\\\\m = 6.4\ x\ 10^7\ kg

Therefore, the density will be:

Density = \frac{m}{V} = \frac{6.4\ x\ 10^7\ kg}{2.14\ x\ 10^{12}\ m^3}

<u>Density = 3 x 10⁻⁵ kg/m³</u>

4 0
3 years ago
In deserts the temperatures can reach extreme values in deep of summer and winter. A steel bridge is being constructed and it is
ryzh [129]

Answer:

The length of the bridge during the hottest part of summer is L_s  = 1235.925 m

Explanation:

From the question we are told that

    The length of the steel bridge is L = 1234.567m

     The temperature for this length is T_1 = 233.15K

     The temperature at summer T_2  = + 140.0F = \frac{140 - 32}{180} *100  + 273= 333 K

     The coefficient of linear expansion is \alpha  = 11.0123*10^{-6} K^{-1}

Generally the change in length of the steel bridge is mathematically represented as

             \Delta L = \alpha L \Delta T

Substituting value

             \Delta L = 11.0123*10^{-6}  * 1234.567 (333-233.15)

              \Delta L = 1.3575 \ m

The length of the bridge in summer is mathematically evaluated as

         L_s  = L + \Delta L

Substituting values

         L_s  = 1234.567 + 1.3575

        L_s  = 1235.925 m

3 0
3 years ago
Please help with all! thank you!!
ahrayia [7]

Answer:

1. Imaginary

2. Latitude

3. Longitude

4. Five

5. Equator

6. Southern

7. Hemisphere

8. Eastern

9. Parallels

10. Time Zones

6 0
3 years ago
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Sportsmanship means following the rules of the game and respecting the judgment of referees and officials. What is another examp
Ludmilka [50]
Another example of sportsmanship is playing equally with other opponents and treated appropriately.
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4 years ago
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