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Vikki [24]
3 years ago
9

Starting from rest, a crate of mass m is pushed up a frictionless slope of angle theta by a horizontal force of magnitude F. Use

work and energy to find an expression for the crate's speed v when it is at height h above the bottom of the slope. Express your answer in terms of the variables m, F, theta, h, and free fall acceleration g v=
Physics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

v =  sqrt[2*(F*h*cot(theta)-mgh)/m]

Explanation:

Work  = KE + Ug

F*r=1/2mv^2+mgh

1/2mv^2=F*r-mgh

v=sqrt[2(F*r-mgh)/m]

r=h/tan(theta)=h*cot(theta)

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How much net force must be applied to a 250 kg boat to cause an acceleration<br> of +1.8 m/s/s?
DiKsa [7]

Answer:

<h2>450 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 250 × 1.8

We have the final answer as

<h3>450 N</h3>

Hope this helps you

8 0
3 years ago
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A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î
Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

Explanation:

Given that,

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We need to calculate the value \vec{v}\times\vec{B}

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We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

\vec{F}=q(\vec{v}\times\vec{B})

Put the value into the formula

\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)

\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}

|F|=2.6\times10^{-9}\ N

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3 years ago
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Answer:

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