Answer: 5503680
Step-by-step explanation:
The coach wants 2 senior out of 36 so he have
C₃₆,₂ = 36!/( 36 - 2 )! = 36*35*34!/34! = 36 * 35 = 1260
possibilities
Now he also wants 3 juniors out of 14
C₁₄,₃ = 14!/ (14- 3)! = 14*13*12*11!/11! = 14*13*12 = 2184
Now for each pair of senior (from 1260 outcomes) coach has 2184 possiblities therefore
Coach has
2184 * 1260 = 2751840 possibilities to choose from
Again as there are 2 senior to choose for captain we have to multiply by 2 to get the total ways the team could be
2751840*2 = 5503680
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are blue-green-black.
Now the rest of the collection consists of
4 blue
4 green
2 black
and there's space for 2 more marbles in the case.
So the question really asks: "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"
-- Well, there are 10 marbles all together.
So the first one chosen can be any one of the 10,
and for each of those,
the second one can be any one of the remaining 9 .
Total number of ways to pick 2 out of the 10 = (10 x 9) = 90 ways.
-- BUT ... there are not nearly that many different combinations
to wind up with in the case.
The first of the two picks can be any one of the 3 colors,
and for each of those,
the second pick can also be any one of the 3 colors.
So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
Answer:
b x 390 =339
Step-by-step explanation:
Answer:
1177.5 inches
Step-by-step explanation:
Volume of a cylinder = 
, where h is the height
Radius = 10/2 = 5 radius is half the diameter
Height = 3*5 = 15 height is 3 times the radius
V = 3.14 * (5^2) * (15)
= 3.14 *25 * 15
= 1177.5
The value of 1.008 expressed as a mixed number would be 1 and 8/1000, as the value of 8 is in the thousandths position.
