We'll have this following figure drawn in the picture. Since we have an isosceles trapezoid, the diagonals are congruent. According to the conditions of the problem, these diagonals are perpendicular and then we can claim that we'll have right-isosceles triangles in this case. Indeed, ∠OBC = ∠FBD = 45°. Then, in the triangle BFD. BF=FD=23. It means the height is 23 cm. Obtaining this fact, we can easily calculate the area.
y2 = 14
y1 = 2
Solution
m = (14 - 2) / (8 - 2)
m = 4 / 4 = 1
Remark
Why is the slope one? I should be 2 shouldn't it? No because there is a common factor to be taken out -- the common factor is 2Answer:
Step-by-step explanation:
y = 2x - 2
x y
2 2
4 6
6 10
8 14
I will use Desmos to get the line.
The slope should be 2
Formula
Slope (m) = ( (y2 - y1) / (x2 - x1) )
Givens
x2 = 8
x1 = 4
y2 = 14
y1 = 6
Solution
m = ( (14 - 6) / ( 8 - 4)
m = 8 / 4
m = 2
Answer:
C= 17mm
Step-by-step explanation:
Triangle=1/2 rectangle
so therefor a rectangle with similar legnth widht and height has 2 times the vollume of this prism
find volume and half it
V=LWH
V=16*12*8*
V=1536
half it
V=768
volume=768 cm^3
