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tensa zangetsu [6.8K]
3 years ago
14

Find x for all three triangles.

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0
In 13, x=27.496
In 14, x=16.824
In 15, x=51.34° 

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I did this in my head; it would take longer to write it out. I'll show you the trig if need be.
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PLZ HELP IMPORTANT!
ad-work [718]
After you've calibrated the sprayer to know your application rate in gallons per acre, divide that number into the gallons applied with each tankful to find how many acres each tankful covers. Then, multiply the acres per tank by the herbicide needed per acre to find the herbicide to put in each tankful.

Mark me as brainliest please
4 0
2 years ago
!!20 POINTS!!
Sidana [21]

Answer:33.415 through 33.585 Or A

Step-by-step explanation:

You simply take 33.5 and add .085 to 33.5 get your answer.then subtract .085 from 33.5

6 0
3 years ago
1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff
Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If  A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that  f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0
3 years ago
When it was Tess' turn in the "Guess my number game, the gloves were off! She gave Davis the following 10 clues:
astra-53 [7]

The number is 999777888.

S<u>tep-by-step explanation:</u>

Reaching to the answer by solving the clues one by one.

The number is a 9 digit whole number. So it has to be 0 or greater than 0

The number is even .So its last digit will be even.

Each of the digit appears exactly thrice. So there will be three digits used three times each in the number.

Each digit is greater than 6. So there will be no digits less than 7 in the number.

All the digits in each period are same. So a period of three adjacent digits will have same the same digit.for ex.777 is  a period

The number is greater than 7. So the digit in the millions place and higher is 9.

The number is divisible by 3. So the sum of all the digits should be divisible by 3.

The number is divisible by 4. So the number formed by last two digits of the number should be divisible by 4.

Thousands digit is 7.

The number that satisfies all the given conditions is 999777888.

5 0
3 years ago
Does anybody know this ???
Anna11 [10]

Answer:

-7x - 18

Step-by-step explanation:

-4x - 10 - 3x - 8 = - 7x - 18

8 0
3 years ago
Read 2 more answers
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