Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
Given:
The two expressions are
To find:
Whether the given expression are equivalent or non-equivalent.
Solution:
If two expressions are looking different but they are equal after simplification, then they are called equivalent expressions.
The first expression is
The first expression is equal to the second expression after the simplification.
Therefore, the given expressions are equivalent.
Answer:
No, it's not equivalent
Step-by-step explanation:
Try and solve the one with the bracket first. Expand 8(15-r) : 8x15 and 8x-r = 120 - 8r
Therefore, the equation can now be written as:
6r-r + 120-8r + 23-6
Rearrange the like terms together and solve the equation:
6r-r-8r + 120+23-6 = -3r + 137
