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Afina-wow [57]
3 years ago
10

In rabbits, B represents the allele for black coat and b represents the allele for white coat. Black is dominant over white. If

a rabbit has the genotype Bb, what is the rabbit's phenotype?
Chemistry
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

Black

Explanation:

It says it in the question " black is more dominant then white"

o-na [289]3 years ago
7 0

Answer:

A rabbit with Bb genotype will be black coated phenotypically

Explanation:

The question involves a single gene coding for coat color in rabbits. According to the question, the allele for black coat (B) is dominant over the allele for white coat (b). This means that black coat allele (B) will mask the phenotypic expression of the white coat allele (b) in a heterozygous state.

A rabbit with genotype, Bb is said to be heterozygous because it possesses the combination of the two different alleles (dominant and recessive). Since, the 'B' allele (black) is dominant, it will mask the expression of the 'b' allele (white). Hence, the rabbit will phenotypically appear black coated.

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Serggg [28]

Answer:

if this is a mock then just guess

Explanation:

4 0
3 years ago
The answer has to be 3 to 5 sentences for me to get full credit. ❤❤​
shusha [124]
The periodic table is an important but rather dry scientific tool. It lists all the chemical elements, ordered by their atomic numbers. Elements with similar behavior are grouped in the same column (called a group), with metals generally on the left and non-metals (gases) on the right. Rows are called “periods” - hence, periodic table.


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8 0
3 years ago
How many moles are in 2.98x10^23 particles?
Novosadov [1.4K]

Answer:

\boxed {\boxed {\sf 0.495 \ mol}}

Explanation:

We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

The units of particles cancel.

2.98*10^{23}  *\frac { 1 \ mol }{6.022*10^{23 } }}

\frac { 2.98*10^{23}}{6.022*10^{23 } }}  \ mol

0.4948522086 \ mol

<h3>2. Round</h3>

The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.

For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

0.495 \ mol

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

3 0
3 years ago
Mercury is a liquid metal having a density of 13.6 gml what is the volume of 1.00 lb of mercury metal
tresset_1 [31]

The volume of 1.00 lb of mercury metal : 33.352 ml

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Density of metal(mercury) = 13.6 g/ml

mass of mercury : 1 lb = 453,592 g

So the volume :

\tt V=\dfrac{453,592~g}{13.6~g/ml}\\\\V=33.352~ml

7 0
3 years ago
What is the percent of S in
ollegr [7]

The percentage of the sulfur (S) in the compound CuSO₄ is 20.1 %.

<h3>What is the mass percentage?</h3>

The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.

First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.

Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.

The molecular mass of CuSO₄ =  63.55 + 32.07 + 4(16.0)  = 159.62 g

The mass percentage of the sulphur = (32.07/159.62) × 100 = 20.1 %

Therefore, the mass percentage of the sulfur is equal to 20.1 %.

Learn more about  the mass percentage, here:

brainly.com/question/16750428

#SPJ1

7 0
1 year ago
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