Answer is: 0,453 <span> moles of oxygen will react </span><span>with 0.3020 moles of carbon(IV) oxide</span><span>.
</span>n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.
Answer:
The allowable values for the principle quantum number (n) are integers greater than zero.
The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.
The allowable values for the magnetic quantum number (ml) are integers from -l to l.
The allowable values for the spin quantum number (ms) are -1/2 and 1/2.
Explanation:
<em>Identify allowable combinations of quantum numbers for an electron. Select all that apply.</em>
- <em>The allowable values for the principle quantum number (n) are integers greater than zero. </em>TRUE. The principal quantum number (n) represents the level of energy in which an electron is and can take positive integer values.
- <em>The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.</em> TRUE. The angular quantum number (l) represents the sublevel of energy and the kind of orbital an electron is in and can take integer values from 0 to n-1. For instance, if n = 1, l can take the value "0", which represents the sublevel and orbital "s".
- <em>The allowable values for the magnetic quantum number (ml) are integers from -l to l.</em> TRUE. The magnetic quantum number (ml) represents the orientation of an orbital in space and can take integers values from -l to +l. For instance, if l = 1 (p orbital), ml can take the values -1, 0 and 1, which refer to orbitals px, py and pz.
- <em>The allowable values for the spin quantum number (ms) are -1/2 and 1/2. </em>TRUE. The spin quantum number (ms) represents the spin of the electron and can take values -1/2 and +1/2.
C is the answer i believe
I hope this helps! please tell me if it’s wrong.
