1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
astraxan [27]
3 years ago
9

You burn a 15g jellybean to warm 50 mL of water, which increases the temperature of the water 25 °C. How many calories of heat a

re transferred from the jellybean to the water? Assume there is no heat loss.
Chemistry
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

Q = 375\,cal

Explanation:

The quantity of heat transfered from the jellybean to the water is:

Q = \rho\cdot V \cdot c\cdot \Delta T

Q = \left(1\,\frac{g}{cm^{3}}\right)\cdot (15\,cm^{3})\cdot \left(1\,\frac{cal}{g\cdot ^{\circ} C} \right)\cdot (25\,^{\circ}C )

Q = 375\,cal

vekshin13 years ago
4 0

Answer:

1.25 Kcal

Explanation:

The relationship between heat and temperature change is given by the equation:

H=mc_p\Delta T

where H = heat energy (Joules, J) , m = mass of a substance (kg) , c = specific heat (units J/kg∙K) and ΔT is the change in temperature

Given that:

mass of water (m) = density of water × volume = 1g/ml × 50ml = 50 g, ΔT = 25° C and c_p of water= 4.18J/g/°C

Therefore H = 50g × 4.18J/g/°C × 25°C = 5225 J

The heat transferred to the Jelly bean = 5225 J = 1.25 Kcal

You might be interested in
Los electrónes casi no tienen
kondaur [170]

Answer:

yedd

Explanation:

5 0
3 years ago
Metals react by what electrons?
fomenos

Answer:

valence electrons

Explanation:

5 0
3 years ago
Commercial hydrochloric acid (HCl) is typically labeled as being 38.0 % (weight %). The density of HCl is 1.19 g/mL. a) What is
Strike441 [17]

<u>Answer:</u>

<u>For a:</u> The molarity of commercial HCl solution is 12.39 M.

<u>For b:</u> The molality of commercial HCl solution is 16.79 m.

<u>For c:</u> The volume of commercial HCl solution needed is 2.42 L.

<u>Explanation:</u>

We are given:

Mass % of commercial HCl solution = 38 %

This means that 38 grams of HCl is present in 100 grams of solution.

To calculate the volume of solution, we use the equation:

Density=\frac{Mass}{Volume}

Density of HCl solution = 1.19 g/mL

Mass of solution = 100 g

Putting values in above equation:

1.19g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=84.034mL

  • <u>For a:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = ?

Molar mass of HCl = 36.5 g/mol

Volume of solution = 84.034 mL

Mass of HCl = 38 g

Putting values in above equation, we get:

\text{Molality of commercial HCl solution}=\frac{38\times 1000}{36.5\times 84.034}\\\\\text{Molality of commercial HCl solution}=12.39M

Hence, the molarity of commercial HCl solution is 12.39 M.

  • <u>For b:</u>

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (HCl) = 38 g

M_{solute} = Molar mass of solute (HCl) = 36.5 g/mol

W_{solvent} = Mass of solvent = 100 - 38 = 62 g

Putting values in above equation, we get:

\text{Molality of commercial HCl solution}=\frac{38\times 1000}{36.5\times 62}\\\\\text{Molality of commercial HCl solution}=16.79m

Hence, the molality of commercial HCl solution is 16.79 m.

  • <u>For c:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated solution

M_2\text{ and }V_2 are the molarity and volume of diluted solution

We are given:

M_1=6M\\V_1=5.00L\\M_2=12.39M\\V_2=?L

Putting values in above equation, we get:

6\times 5=12.39\times V_2\\\\V_2=2.42L

Hence, the volume of commercial HCl solution needed is 2.42 L.

5 0
3 years ago
Which molecule is a substrate dipeptide, water or amino acid?
Leona [35]
Amino acids.
Amino acids group together to form proteins. Enzymes are protein in nature. Thus the substrate is an amino acid.

Hope it helped!
5 0
4 years ago
The amount of energy required to raise the temperature of a swimming pool depends on the mass of water present.
cluponka [151]
True. Refer to the heat equation of water
3 0
3 years ago
Other questions:
  • Consider the function f(x) =
    12·1 answer
  • How many moles of HNO3 will be produced 3 NO2+H2O=2HNO3+ NO
    11·1 answer
  • How many moles of Ag will be produced from 46.0 g of Cu, assuming AgNO3 is available in excess?
    14·1 answer
  • Give the formulas for all of the elements that exist as diatomic molecules under normal conditions. See if you can do this witho
    14·1 answer
  • Which of the following pairs of elements is most likely to form an ionic bond? A. nitrogen and oxygen B. aluminum and nitrogen C
    8·1 answer
  • A metallic substance has a volume of 10.5 cm' and a mass of 81.9 grams.What is the density of this substance
    14·1 answer
  • Determine the pH at the point in the titration of 40.0 mL of 0.200 M H₂NNH₂ with 0.100 M HNO₃ after 100.0 mL of the strong acid
    11·1 answer
  • help please an btw this isn't a test ill give brainliest science is really my thing. btw help with number 6
    11·1 answer
  • Brainiest plsss helpp
    12·2 answers
  • I need help on this, It’s due today. Please, anybody
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!