Male is 66% brown is 50% both is 58% and there are two male puppies
c) Combine 2+3 to get 5. 100-(5x5) equals 100-25. 100-25 is 75. The answer is 75.
d) Combine 2+3 to get 5. Combine 1+4 to get 5, which is 25. The answer is 5.
g) Combine 4+6 to get 10. Combine 70+-6 to get 64. Take the root of 64, leaving you with 10-8. Combine 10 + -8 to get 2. The answer is 2.
h) Combine 5+4 to get 9. Take the root of 36, leaving you with 18 + 6. Combine 18 + 6 to get 24. The answer is 24.
5. [15 + 22 + 53] divided by [12 + 18] = [90] divided by [30] = 3 ribbons each.
6. (4 x 12) + (6 x 8) = 96 total.
Y intercept = when x = 0
Plug in x = 0
0 + 3y = 6
3y = 6, y = 2
Solution: a, (0,2)
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
i think the answer is -50 but im
not sure