The sum of all three is 6x^2y + 2xy^2
I’m so sorry I need points but I’m gonna manifest that someone smarter will see this and answer
Answer:
odd
Step-by-step explanation:
Just so you know there are shortcuts for determining if a polynomial function is even or odd. You just to make sure you use that x=x^1 and if you have a constant, write it as constant*x^0 (since x^0=1)
THEN!
If all of your exponents are odd then the function is odd
If all of your exponents are even then the function is even
Now you have -4x^3+4x^1
3 and 1 are odd it is an odd function
This a short cut not the legit algebra way
let me show you that now:
For it to be even you have f(-x)=f(x)
For it be odd you have f(-x)=-f(x)
If you don't have either of those cases you say it is neither
So let's check
plug in -x -4(-x)^3+4(-x)=-4*-x^3+-4x=-4x^3+-4x
that's not the same so not even
with if we factor out -1 .... well if we do that we get -(4x^3+4x)=-f(x)
so it is odd.
<span>Here, Elaine = Tyler + (-8)
</span>⇒ E<span>laine + 0 + Tyler + 0 = 34
</span>⇒ T<span>yler + (-8) + 0 + Tyler + 0 = 34
And, Tyler = [(34 - (0) - (-8)] / 2
Thus, Tyler = 21
And, Elaine = 21 + (-8)
=13
</span>∴ T<span>yler = 21 & Elaine = 13
Regards
#Exotic Explorer</span>
