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Troyanec [42]
3 years ago
9

Does anyone know how to solve this??

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0
Volume of a cone = (1/3) x Area of the base (B) x height(h)
V = (1/3)·420·180
   = 25200 mm³
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Show all of your work. Simplify the expression: - 3a + 7 + 5a​
Eva8 [605]

Answer:

2a + 7

Step-by-step explanation:

-3a + 7 +5a

<em>subtract the negative 3 from the 5</em>

2a + 7

4 0
3 years ago
Read 2 more answers
Cameron has 2 video game holder stands each can hold 2 rows of 20 games write and evaluate a numerical expression to find the to
Aleksandr [31]

Answer:

so this would be the equation

2(2*10)=v

So the number on the outside is the number of stands, the second 2 is for the two rows, and the 10 is the games. I did this because its two rows and combined they make 20 games. It took me a little to figure that out.

This shows the number of games total in both holders.


5 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
Use compatible numbers to find two estimates: 17 ÷1569
Mekhanik [1.2K]
I dont know what you mean but i devided 17 and 1569 and it =s 0.0108349267
7 0
3 years ago
Does anyone understand this?. I also have to show my work.
snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

Step-by-step explanation:

Given equation is C=\frac{5}{9}(F -32)

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=0.

For F = 41.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(41 -32)

C=05

For F = 50.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(50 -32)

C=10

For F = 59.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=15

<em>Note: The figure shows a graph of given equation with points.</em>

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

<em>C=18.333333.</em>

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=\frac{5}{9}(F -32)

0=\frac{5}{9}(F -32)

0=(F -32)

F=32 Temperature.

Ans D). Slope of the line C=\frac{5}{9}(F -32)

The slope of line is given by s= \frac{Y1-Y2}{X1-X2}

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= \frac{Y1-Y2}{X1-X2}

s= \frac{0-5}{32-41}

s= \frac{5}{9}

Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

7 0
3 years ago
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