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muminat
3 years ago
13

I need help with this question help me

Mathematics
1 answer:
vekshin13 years ago
7 0
Fourth root (3/2x)
= [fourth root {3*(2x)^3}  / {2x * (2x)^3}]
= [fourth root (3*8x^3}) /(2x)^4]
= [fourth root (24x^3)] / 2x

answer is B. second one


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Find an equation of the line passing through the points (5, 21) and (-5, -29)
gogolik [260]
Trata 5-29+-5=21 porque ya as tenido este
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Write the expression in standard form<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B3-15i%7D" id="TexFormula1" title="\
valentina_108 [34]

<em>Answer:</em>

<em>7/78 - 35/78i</em>

<em>Step-by-step explanation:</em>

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<em>a + bi </em>

<em> </em>

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4 0
2 years ago
Given klmn is a trapezoid, kl = mn, m&lt;1 = m&lt;2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
Ilia_Sergeevich [38]

Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

This leads the two set of legs such as

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Or this could be written as

lm=8x\\kn=9x

Now the remaining two sides are given as

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Similarly

mn=lm\\

Or

mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

So the four legs are of length as given below:

lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

So the length of legs lm, mn, and lk is 32 while that of kn is 36.

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