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tamaranim1 [39]
3 years ago
5

A rectangular greenhouse has an area of 6,480 square meters. Its length is 120 meters.

Mathematics
2 answers:
Marat540 [252]3 years ago
7 0

Answer:

3.5

Step-by-step explanation:

kari74 [83]3 years ago
3 0
The answer is 3.5 you’ll thank me later
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If somebody laugh at everything is that a annoyed
andreyandreev [35.5K]

Answer:

the question made no sense.

Step-by-step explanation:

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2 years ago
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Does anyone know how to answer this question I'm having a lot of trouble with it?
Helen [10]

Answer:

h = \frac{2A}{(b+c)}

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = \frac{1}{2}(b+c)h

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = 2[\frac{1}{2}(b+c)h]

2A = (b + c)h

\frac{2A}{(b+c)}=h

Therefore, formula for the height of the trapezoid will be,

h = \frac{2A}{(b+c)}

5 0
2 years ago
Write an expression to represent:<br> 6 times the difference of 5 and 2.​
Keith_Richards [23]

Answer:

See below

Step-by-step explanation:

The difference of 5 and 2    

    5-2    <=====   now multply it by 6

6 x (5-2)

4 0
2 years ago
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Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4.
meriva

Answer:

Option C.

Step-by-step explanation:

The given logarithmic equation is

\log_2(x+11)=4

It can be written as

(x+11)=2^4     [\because log_ax=y\Leftrightarrow x=a^y]

x+11=16

x=5

Now, to check whether x=5 is a true solution or not. Substitute x=5 in the LHS of given equation.

LHS=\log_2(5+11)

LHS=\log_2(16)

LHS=\log_22^4

LHS=4     [\because log_aa^x=x]

LHS=RHS

Hence, x=5 is a true solution because \log_2(16)=4.

Therefore, the correct option is C.

5 0
2 years ago
Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data
Bad White [126]

Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

Interquartile range =3

City B

Maximum - Minimum = 18.5

Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

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3 years ago
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