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3 years ago

13

Jacques needs to convert the function f(x) = x2 − 6x + 14 to vertex form, f(x) = (x − h)2 + k, in order to find the minimum.

1 answer:

Bond [772]3 years ago

4 0

Answer:

C. 5

Step-by-step explanation:

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Ms. Cassidy plotted the point (2, 3) on Miguel’s graph of y < 2x – 4. She instructed him to change one number or one symbol i

elixir [45]

Answer:

C, D,F

Step-by-step explanation:

5 0

3 years ago

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Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago

For g(x) = 1/3x – 2, find the value of x for which g(x) = -4

kirill [66]

Answer is attached ! Hope it helps

5 0

2 years ago

Consider the steps for determining the quotient of 12/x-4 / 4/x-4

Ierofanga [76]

Answer:

Quotient = 3

Step-by-step explanation:

We need to solve the given expression :

$\dfrac{\dfrac{12}{x-4}}{\dfrac{4}{x-4}}$

It can be done as follows :

As, $\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}$

So,

$\dfrac{\dfrac{12}{x-4}}{\dfrac{4}{x-4}}=\dfrac{12}{x-4}\times \dfrac{x-4}{4}\\\\=\dfrac{12}{4}\\\\=3$

Hence, the required quotient is 3.

5 0

3 years ago

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In circle o, which term correctly identifies line XY?

Alex

B.Chord.Hope this helped.

4 0

3 years ago

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