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tekilochka [14]

3 years ago

15

An accounting firm purchased a new digital camera that cost $2,500. The life of the camera is estimated to be 5 years. The total

salvage value after 5 years of use is estimated to be $700. Using the straight-line method, find the annual depreciation of the camera.

1 answer:

lozanna [386]3 years ago

5 0

2500-700 = 1800
1800/5 = 360

The annual depreciation of the camera is $360.

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Please help this is due in tommorow! I will mark you as brainliest!

pshichka [43]

Answer:

325.26

Step-by-step explanation:

that's the answer because you have to multiply the top

I have question do we have to do something to the bottom?

5 0

3 years ago

A random sample of 100 observations from a quantitative population produced a sample mean of 22.8 and a sample standard deviatio

natima [27]

Answer:

We conclude that the population mean is 24.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, $\bar{x}$ = 22.8

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 8.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 24\\H_A: \mu \neq 24$

We use Two-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{22.8 - 24}{\frac{8.3}{\sqrt{100}} } = -1.44$

We calculate the p-value with the help of standard z table.

P-value = 0.1498

Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.

Now, $z_{critical} \text{ at 0.05 level of significance } = \pm 1.96$

Since, the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.

7 0

3 years ago

I had $25 and i bought 3 boxes of granola bars. i can home with $4. how much does each box of granola bars cost?

Snezhnost [94]

$25 - $4 = $21
You spent $21 on 3 boxes of granola bars.

3 boxes = $21
1 box = $21 ÷ 3 = $7

One box of granola bar costs $7.

4 0

3 years ago

Read 2 more answers

HELP ME A.S.A.P. PLZZZZ

Ronch [10]

Answer:

A = 66.5 in²

Step-by-step explanation:

There are a few different equations to find the area of a rhombus. If you are given the measurements of the two diagonals, you can use the following formula:

Area (A) = $\frac{d_{1}d_{2} }{2}$

Using this formula, you can multiply the measures of the diagonals and then divide by 2:

area = $\frac{(9.5)(14)}{2} =\frac{133}{2}=66.5in^{2}$

7 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago