A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>
Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
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Answer:
y = 2
Step-by-step explanation:
3y - 4 = 6 - 2y
+2y +2y
5y - 4 = 6 (new equation)
+4 +4
5y = 10 (new equation)
/5 /5
y = 2
Answer:
6/5
Step-by-step explanation:
m is your rate of change you need to get y by itself.
3/2x - 15 = 5/4y
3x/2 - 30/2 = 5/4y
3x-30/2 = 5/4y
3x - 30 = 2 x 5/4y
3x - 30 = 2 x 5/4x2y (cross out 2 and 4)
3x - 30 = 5/2y
2 x 3x - 2 x 30 = 2 x 5/4y
6x - 60 = 5y
6x/5 - 60/5 = 5y/5
y = 6/5 x x - 12
145. u take 180 subtract 35. It will gives u 145
