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inysia [295]
3 years ago
15

Which transformations have been performed on the graph of f(x) =

Formula1" title="\sqrt[3]{x}" alt="\sqrt[3]{x}" align="absmiddle" class="latex-formula"> to obtain the graph g(x) = 1/4\sqrt[3]{x+3} + 6
Select each correct answer.



(A) reflect the graph over the x-axis

(B) compress the graph closer to the x-axis

(C) translate the graph down

(D) translate the graph to the right

(E) translate the graph to the left

(F) translate the graph up

(G) stretch the graph away from the x-axis

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

(B) compress the graph closer to the x-axis

(E) translate the graph to the left

(F) translate the graph up

Step-by-step explanation:

When functions are transformed there are a few simple rules:

  • Adding/subtracting inside the parenthesis to the input shifts the function left(+) and right(-).
  • Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).
  • Multiplying the function by a number less than 1 compresses it towards the x-axis.
  • Multiplying the function by a number greater than 1 stretches it away from the x-axis.

This graph has been multiplied by 1/4 which is less than 1. It will be compressed.

This graph has x added to by 3. It will shift left 3 units.

This graph has the output outside of x added to by 6. It will shift 6 units up. See picture below. The original function is red. The new function is blue.



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3 years ago
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Which congruence statements are true? Choose all answers that are correct?<br><br> A: B: C: D:
tester [92]

Answer:

Correct choices are A and C

Step-by-step explanation:

Inscribed angles property: The inscribed angles subtended by the same arc are equal.

1. Angles EFH and EGH are both inscribed angles subtended by the arc EH. Therefore, these angles are congruent (option A is true).

2. Angles GHF and GEF are both inscribed angles subtended by the arc GF. Therefore, these angles are congruent (option C is true).

3. Angles EGH and FHG are interior angles of the triangle KGH and can be congruent (if triangle is isosceles) or can be not congruent (in general). Thus, option B is false.

4. Angles EFH and FHG in general are not congruent. They can be congruent only when arcs EH and FG have the same measure. In general, option D is false.

4 0
3 years ago
Point m is located at 4,-2 what is located 2 units for point m
eimsori [14]

Answer:

None

Step-by-step explanation:

Given

m = (4,-2)

Required

Point 2 units from m

There are 4 possible points 2 units from m and they are:

m' = (4+2,-2) = (6,-2)

m" = (4,-2+2) = (4,0)

m'''= (4-2,-2) = (2,-2)

m'''' = (4,-2-2) = (4,-4)

From the graph, we have:

A = (4,2)

B = (-4,2)

C = (2,-3)

None of the points is 2 units from m

7 0
2 years ago
What is the domain of y = cos ^-1x?
Bas_tet [7]

Answer:

Step-by-step explanation:

Correct option is

D

[1,(1+π)  

2

]

f(x)=(1+sec  

−1

(x))(1+cos  

−1

(x))

Here the limiting component is cos  

−1

(x), since the domain of cos  

−1

(x) is [−1,1].

Therefore,

f(1)=(1+0)(1+0)

=1

f(−1)=(1+π)(1+π)

=(1+π)  

2

 

Hence range of f(x)=[1,(1+π)  

2

]

8 0
2 years ago
The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th
Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

dC = Cv.dv + Ct.dt

Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44

Relative Error

dC / C @(T = 8, v=23)  * 100 = 19 %

8 0
3 years ago
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