Answer:
ΔpH = 1.25
Explanation:
Using Henderson-Hasselbalch formula:
pH = pka + log [CH₃COONa] / [CH₃COOH]
pH = 4.74 + log [0.112] / [0.112]
<em>pH = 4.74</em>
The reaction of sodium acetate (CH₃COONa) with HCl is:
CH₃COONa + HCl → CH₃COOH + NaCl
<em>Producing acetic acid, </em>CH₃COOH.
If 0.1mol of HCl reacts the final moles of CH₃COONa are:
0.112mol - 0,1 mol = 0.012mol
Moles of acetic acid are:
0.112mol + 0,1 mol = 0.212mol
Using Henderson-Hasselbalch formula:
pH = pka + log [CH₃COONa] / [CH₃COOH]
pH = 4.74 + log [0.012] / [0.212]
<em>pH = 3.49</em>
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Change in pH, ΔpH = 4.74 - 3.49 =<em> 1.25</em>
I hope it helps!
