All categories

3 years ago

What is the smallest part of Substance called?

Chemistry

2 answers:

enot [183]3 years ago

3 0

It is definitely a molecule

Triss [41]3 years ago

3 0

The answer is a Molecule.

You might be interested in

If water were a non-polar Molecule

JulijaS [17]

Answer:

Water would not be able to transport nutrients -‐-‐ in plants, or in our bodies -‐-‐ nor to dissolve and transport waste products out of our bodies. ... Cohesiveness, adhesiveness, and surface tension: would decrease because without the +/-‐ polarity, water would not form hydrogen bonds between H20 molecules.

8 0

2 years ago

Would it be D....???? HELPPPPPP

AlekseyPX

Answer:

yes

Explanation:

6 0

3 years ago

Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd

d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25.0 + 273.15) K = 298.15 K

Volume = 1.50 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K

⇒n = 0.1863 moles

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.1863\ mole= \frac{Mass}{4.0026\ g/mol}$

$Mass_{He}= 0.7457\ g$

0.7457 g is the mass of the helium gas.

6 0

2 years ago

Which of the following is equal to 5,800,000,000 cm?

Reil [10]

Answer:

It would be 5.8 times 10^9cm

6 0

2 years ago

A solution was made by adding water to 0.250 g of H2Z until the volume totaled 25.00 mL. Subsequent titration required 40.50 mL

Brilliant_brown [7]

Answer:

123 g/mol

Explanation:

Let's consider the neutralization reaction.

H₂Z(aq) + 2 NaOH(aq) → Na₂Z(aq) + 2 H₂O(ℓ)

The moles of NaOH that reacted are:

$40.50 \times 10^{-3} L \times \frac{0.100molNaOH}{1L} =4.05\times 10^{-3} molNaOH$

The molar ratio of H₂Z to NaOH is 1:2. The moles of H₂Z that reacted are:

$4.05\times 10^{-3} molNaOH \times \frac{1molH_{2}Z}{2molNaOH} =2.03\times 10^{-3} molH_{2}Z$

The molar mass of H₂Z is:

$\frac{0.250gH_{2}Z}{2.03\times 10^{-3} molH_{2}Z} =123g/mol$

7 0

3 years ago