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asambeis [7]
3 years ago
15

The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 47 calories of heat.

What is the specific heat of iron?
Chemistry
1 answer:
hichkok12 [17]3 years ago
5 0
Q  =  mc(θ₂-θ₁)

47 calories =  10 g *c*(50.4 - 25)

47cal = 10*c* 25.4

47 /(10*25.4) = c

0.185 = c

Specific heat of iron = 0.185 cal/g°C 
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