Answer:
Explanation:
Your goal here is to figure out the mass of iron and the mass of sulfur present in exactly
100 g
of this compound, which is what you need in order to know the compound's percent composition.
The problem provides you with the mass of iron and with the mass of sulfur present in
27.9 g
of this compound, so you must use this information to scale up your sample from
27.9 g
to
100 g
.
To do that, set up the known composition of the compound as a conversion factor.
To find the number of grams of iron present in
100 g
of compound, set up the conversion factor like this
17.6 g iron
27.9 g compound
You will end up with
100
g compound
⋅
17.6 giron
27.9
g compound
=
63.1 g iron
To find the mass of sulfur present in
100 g
of compound, you can either use a conversion factor set up in a similar manner
100
g compound
⋅
10.3 g sulfur
27.9
g compound
=
36.9 g sulfur
or use the fact that the compound contains only iron and sulfur to say that the mass of sulfur will be equal to
100 g compound
−
63.1 g iron = 36.9 g sulfur
You now know the mass of iron and the mass of sulfur present for every
100 g
of compound, so you can say that the compound has the following percent composition
63.1% iron
36.9% sulfur
Here
%
means per
100 g
of compound.
Answer:
A molecule of sucrose (C12H22O11) has 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms. The subscripts also indicate the ratios of the elements.
Explanation:
This is because it has the abbreviation of the Carbon atoms, Hydrogen atoms, and Oxygen atoms are right before the number.
A strong electrolyte is completely ionized. Ex: NaCl --h2o--> Na^+(aq) + Cl^-(aq)
Answer:
3 bags are required.
Explanation:
Find the number of mg needed for 150 pounds
150 pounds * 5 mg/pound = 750 mg
1 bag = 250 mg
x bags = 750 mg Cross multiply
250 * x= 750 Divide by 250
x = 750/250
x = 3
