The steps are to first distribute the 1/3 into (x-9) and then to move the +6 on the left over to the right:
First distribute:
y + 6 = 1/3(x-9) becomes y + 6 = 1/3x-3
Now subtract 6 from both sides:
y = 1/3 x - 3 - 6
y = 1/3 x - 9
Answer:
- the value of the function changes sign in the interval
- the function is monotonic in the interval
Step-by-step explanation:
All polynomial functions are continuous, so we know from the intermediate value theorem that if the expression on the left changes sign in the interval [-2, 1] then there will be a zero in that interval. If the function is monotonic in the interval, there can only be one zero.
a) For f(x) = x^3 +x +3 = (x^2 +1)x +3, the values at the ends of the interval are ...
f(-2) = (4+1)(-2) +3 = -7
f(-1) = (1 +1)(-1) +3 = 1
The function value goes from -7 to +1 in the interval, so there exists at least one root in that interval.
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b) The derivative of the function is ...
f'(x) = 3x^2 +1
This is positive for any x, so is positive in the interval [-2, -1]. That is, the function is continuously increasing in that interval, so cannot have more than one crossing of the x-axis. There is exactly one root in the interval [-2, -1].
Answer:
x=5 y=8
Step-by-step explanation:
here's your answer. Please mark as brainliest
we know the triangle is an isosceles, so it has twin sides, and then the hypotenuse, since it's a right-triangle, we can just use the pythagorean theorem for that.
Answer:
F
Step-by-step explanation: