Answer: 
Step-by-step explanation:
Equilateral triangle has equal sides, let the side be
, then the perimeter is 
Therefore:



To find the altitude , we will apply Pythagoras theorem , that is

Therefore:



take the square root of both sides

Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
Answer:
g(x)=(x+7)^2-3
Step-by-step explanation:
Given:
f(x)= x^2
Now we have to translate f(x) 7 units to the left and 3 units down to form the function g(x).
As per the rules of translation
when any parent function, in given case f(x)=x^2, is translated to 'a' units to the left then 'a' is added to the value of x. thus making f(x+a)
Also when the parent function is translated any 'a' units down then 'a' is subtracted from the value of function. thus making f(x)-a
Translating f(x), 7 units to the left
f(x+7)= (x+7)^2
Translating f(x+7), 3 units down
f(x+7)-3 = (x+7)^2-3
Hence new function g(x)=(x+7)^2-3!
Answer:
$98.75
Step-by-step explanation:
50×75÷100 = 37.5 + 50 = 87.5
87.5 × 30 ÷ 100 = 26.5
87.5 - 26.5 = 61.25
87.5 + 61.25 = 148.75
148.75 - 50 = 98.75
i hope i am right
Step-by-step explanation: A line, ray, or line segment (referred to as segment) that is perpendicular to a given segment at its midpoint is called a perpendicular bisector. ... In the diagram above, RS is the perpendicular bisector of PQ, since RS is perpendicular to PQ and PS≅QS. Additionally, since PS≅QS, point S is the midpoint of PQ.