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aliina [53]
3 years ago
6

A treasury has 500 7-ounce weights, 500 11-ounce weights, and a balance. a foreign dignitary arrives with a gold bar, claiming i

t to weigh 500 ounces. can the treasury determine whether the dignitary is telling the truth? if so, how?
Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Yes the treasury can determine whether the gold bar is really weighing 500 ounces.

We can use the equation:

7 x + 11 y = 500

where x is the amount of the 7 ounce weights while y is the amount of 11 ounce weights.

 

We know that x and y should be whole numbers therefore this is solved through trial and error.

By trial and error I got:

x = 7 and y = 41

<span>
So that;</span>

7 * 7 + 11 * 41 = 500

49 + 451 = 500

500 = 500

 

<span>Hence they can use 41 11-ounce weights and 7 7-ounce weights to test</span>

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enot [183]

Answer:

X°

Step-by-step explanation:

there’s no other clues to what it could be, and since it’s x it would be X°

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3 years ago
What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)
kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2)  \right )^{2}+\left (6-2  \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0
3 years ago
Hana is playing a virtual reality game in which she must toss a disc to land on the largest triangular section of the board. If
svetoff [14.1K]

Answer:

Her probability of success is 1/2

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Firstly, we have to calculate the area of the entire board

That would be the rectangle of the measure 50 cm by 40 cm

We have the area as the product of this two

That would be 50 * 40 = 2,000 cm^2

Now, the value calculated is the area of the entire possible landing area

Secondly, we need to get the area that counts as a success

that would be the area of the triangle that has a base of 50 cm and a height of 40 cm

The area of this is the product of the two divided by 2

we have this as ;

50 * 40 * 1/2 = 1,000 cm^2

So, her probability of success is simply the area of the triangle divided by the area of the rectangle

= 1000/2000 = 1/2

8 0
2 years ago
A man travelled 3/8 of his journey by a rail 1/4 by a taxi 1/8 by and the remaining 2km on foot what is the length of his total
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The man travelled in different ways: by rail, by taxi, by ___ and by foot. I placed a blank there because there seems to be a missing word in the given problem above. For sample purposes, let's just assume that is travel by bus.

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That means that the travel by foot comprises 1/4 of the whole journey. Thus,

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456,912-37,800 estimate
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i think it might be around 440,112

7 0
2 years ago
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