I need help with table “A”
1 answer:
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Answer:
The required probability is 0.09875
Step-by-step explanation:
From the given information;
the probability of repairing the telephones = 0.70
the probability of the replaced = 0.30
Suppose we consider Mto denotes the telephone that is submitted for service while under warranty and must be replaced.
Then;
p = P(S) = P(replaced | submitted) P(submitted)
= 0.30 × 0.20
= 0.06
Now, the probability that exactly two will end up being replaced under warranty given that it assumes a binomial distribution where n = 10 and p = 0.06