To find slope you do y2-y1 over x2-x1. So 4-6 is -2. And 3-1 is 2. So -2/2 is -1. The slope is -1.
Answer:
13
Step-by-step explanation:
Replace X with 2
Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)
g(x) = 3(2)^2 – 2(2) + 5
Next conduct PEMDAS
Exponents are first so solve 2^2 which is 2 x 2 = 4
g(x) = 3(4) – 2(2) + 5
Next step is multiplication multiply 3 x 4 and 2x2
g(x) = 12 – 4 + 5
conduct adding and subtracting left from right
g(x) = 13
Well u would turn 4 into a decimal. this is 0.04. then multiply it by 16. that answer will be added to the original price 16. this would be the answer.
Step-by-step explanation:
slope formula when it's perpendicular : m1 × m = -1
Now Differentiate the quadratic function given.
d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"
= 2x - 1 .... plug in the x value
= 2 × -1 - 1 = -3.
Use this equation...
y - y1 = m(x - x1)
m = slope = derivative at x = -1
y1 = value found by subbing -1 into the original function
x1 = the x value often given.
y - 3 = 1/3 (x + 1)
= 1/3x + 1/3 + 3
y = 1/3x + 10/3.
not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.
y = 0 + 10/3 = 10/3
1/3x = 0 - 10/3
x = -10/3 / 1/3 = -10
so the point .... (-10 , 10/3)
Answer:
<em>908360.67 lb-ft</em>
<em></em>
Step-by-step explanation:
height of tank= 6 ft
diameter of the tank = 4 ft
density of water p = 62.4 lbs/ft
A is the cross sectional area of the tank
A = 
where r = diameter/2 = 4/2 = 2 ft
A = 3.142 x
= 12.568 ft^2
work done = force x distance through which force is moved
work = F x d
Force due to the water = pgAh
where g = acceleration due to gravity = 32.174 ft/s^2
Force = 62.4 x 32.174 x 12.568 x 6 = 151393.44 lb
work done = force x distance moved
work = 151393.44 x 6 = <em>908360.67 lb-ft</em>