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3 years ago

What is the area of the shape

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

To find the area of a rhombus, the formula is d1(d2)/2
d1 is 4+4 or 8
d2 is 7+10 or 17
17(8)=136
136/2=68

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Solving Exponential and Logarithmic Equations In Exercise, solve for x. In 2x - In(3x - 1) = 0

LenKa [72]

Answer:

$\frac{-1}{3x^2-x}$

Step-by-step explanation:

If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

using these information:

g(x)=ln2x then g'(x)= $\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}$

h(x)=In(3x - 1) then h'(x)= $\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}$

7 0

4 years ago

Yeah so help please.

irina [24]

Answer:

could you possibly zoom in

Step-by-step explanation:

7 0

3 years ago

Square root of 75 plus square root of 3

olya-2409 [2.1K]

Answer:
6√3

Explanation:
Before we begin, remember the following:
$\sqrt{a*b} = \sqrt{a} * \sqrt{b}$
$m \sqrt{a} + n \sqrt{a} = (m+n) \sqrt{a}$

Now, for the given:
75 can be written as 25*3
This means that:
$\sqrt{75} = \sqrt{25*3}$
Applying the above concept, we can find that:
$\sqrt{75} = \sqrt{25*3} = \sqrt{25} * \sqrt{3}$
Now, we know that:
√25 = 5 (we ignored the negative value)

This means that:
√75 = 5√3

Finally, we can compute the needed sum as follows:
√75 + √3 = 5√3 + √3 = 6√3

Hope this helps :)

8 0

3 years ago

Read 2 more answers

How do i simplify this equation?

elixir [45]

Answer:

-6 = m (i'll show my work below)

Step-by-step explanation:

-6(m-7) + 7 = -8m + 37

-6m + 42 + 7 = -8m + 37

-6m + 49 = -8m +37

-37 = -37

-6m + 12 = -8m

+6m = +6m

12 = -2m

/-2 = /-2

-6 = m

8 0

3 years ago

Simplify (8.3) 2.10.(6-1)

vagabundo [1.1K]

Answer:

$8 .3 \times 2.10.5$

Step-by-step explanation:

Simplify 6 - 1 to 5.

$8.3 \times 2.10 .5$

Therefor, the answer is 8.3 × 2.10.5

6 0

3 years ago