What substance is used in the industrial preparation of methyl diantilis to reduce the aldehyde group of 3-ethoxy-4-hydroxybenza
ldehyde?
1 answer:
Answer:
Sodium Borohydride (NaBH₄)
Explanation:
Methyl diantilis (2-Ethoxy-4-(methoxymethyl)phenol) is a fragrance compound which smells like Vanilla. This compound is being synthesized from 3-ethoxy-4-hydroxybenzaldehyde also known as Ethyl Vanillin in two steps.
Step 1: Reduction of Aldehydic Group on Ethyl Vanillin:
The benzaldehyde derivative is treated with a mild reducing agent i.e. NaBH₄ (Sodium Borohydride). NaBH₄ is a source of Hydride (H⁻) ion and undergoes nucleophilic substitution reaction yielding 2-ethoxy-4-(hydroxymethyl)phenol.
Step 2: Etherification of 2-ethoxy-4-(hydroxymethyl)phenol:
In the second step 2-ethoxy-4-(hydroxymethyl)phenol is treated with Methanol in the presence of strong acidic polymeric resin known as Amberlyst-15-wet resulting in the formation of Methyl diantilis as shown in attached figure.
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Answer : The volume of gas is,
Explanation : Given,
Mass of S = 4.10 kg = 4100 g (1 kg = 1000 g)
Molar mass of S = 32 g/mol
First we have to calculate the moles of S.
Now we have to calculate the moles of
The balanced chemical reaction is:
From the balanced reaction, we conclude that
As, 1 mole of react to give 1 mole of
So, 128.125 mole of react to give 128.125 mole of
Now we have to calculate the volume of by using ideal gas equation.
where,
P = Pressure of gas = 1.16 atm
V = Volume of gas = ?
n = number of moles = 128.125 mole
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
(1 L = 1000 mL)
Therefore, the volume of gas is,
The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.
<h3>What are moles?</h3>A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Given data:
Moles of hydrochloric acid = 0.385 mol
Mass of chlorine gas =?
Chemical equation:
4HCl + O₂ → 2Cl₂ + 2H₂O
Now we will compare the moles of Cl₂ with HCl.
HCl : Cl₂
4 : 2
0.385 : 2÷4× 0.385 = 0.1925 mol
Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.
Mass of Cl₂ :
Mass of Cl₂ = moles × molar mass
Mass of Cl₂ =0.1925 mol × 71 g/mol
Mass of Cl₂ = 13.6675 g
Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.
Learn more about moles here:
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