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galina1969 [7]
3 years ago
13

Complete the table with the mass number, number of protons, number of neutrons, and number of electrons for the elements shown.

Chemistry
1 answer:
Alex3 years ago
6 0

Answer:

Explanation:

The Proton number for flourine will be 9

Then the mass number which will be protons+ neutrons will be 19

Argon which has a mass number of 40

to find the proton number of argon it will be 40-22=18

then the electron number will just be the same as proton number

then calcium the proton will be the same as electron so it will be 20

then neutrons will be mass number -proton number

which is 21

hope this helped

and pretty cool you use a mac

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Doesn't matter now . It's fine
vfiekz [6]
What are u talking about?? if it was a response you posted it in the wrong place lol. Thanks for the free 5 points tho.
3 0
3 years ago
When calcium reacts with tellurium to form an ionic compound, each metal atom loses electron(s) and each nonmetal atom gains ele
Finger [1]

Answer:

When calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

Explanation:

Calcium has atomic number of 20. Its electronic configuration is given as:

[Ca]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2

Calcium atom will loose 2 elections to attain electronic configuration of noble gas.

[Ca^{2+}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^0

Ca\rightarrow Ca^{2+}+2e^-

Tellurium has atomic number of 52. Its electronic configuration is given as:

[Te]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p4

Tellurium atom will gain 2 elections to attain electronic configuration of noble gas.

[Te^{2-}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p6

Te+2e^-\rightarrow Te^{2-}

So, when calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

Ca^{2+}+Te^{2-}\rightarrow CaTe

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

7 0
3 years ago
A 57.9 gram mass has a volume of 3 cm 3. What is the density of the mass?
Licemer1 [7]

Answer:

<h3>The answer is 19.3 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question

mass = 57.9 g

volume = 3 cm³

We have

density =  \frac{57.9}{3}  \\

We have the final answer as

<h3>19.3 g/cm³</h3>

Hope this helps you

6 0
4 years ago
A student titrated a solution containing 3.7066 g of an unknown Diprotic acid to the end point using 28.94 ml of 0.3021 M KOH so
uranmaximum [27]

Answer:

<u>Molar</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>diprotic</u><u> </u><u>acid</u><u> </u><u>is</u><u> </u><u>4</u><u>2</u><u>4</u><u> </u><u>grams</u>

Explanation:

[hint: <u>diprotic</u><u> </u><u>acid</u><u> </u><u>only</u><u> </u><u>contains</u><u> </u><u>2</u><u> </u><u>hydrogen</u><u> </u><u>protons</u><u>]</u>

Ionic equation:

{ \bf{2OH { }^{ - }  _{(aq)} + 2H { }^{ + } _{(aq)}→  2H _{2} O _{(l)} }}

first, we get moles of potassium hydroxide in 28.94 ml :

{ \sf{1 \: l \: of \: KOH \: contains \: 0.3021 \: moles}} \\ { \sf{0.02894 \: l \: of \: KOH \: contain \: (0.02894 \times 0.3021) \: moles}} \\ { \underline{ = 0.008743 \: moles}}

since mole ratio of diprotic acid : base is 2 : 2, moles are the same.

Therefore, <u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>a</u><u>c</u><u>i</u><u>d</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>r</u><u>e</u><u>a</u><u>c</u><u>t</u><u>e</u><u>d</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>0</u><u>.</u><u>0</u><u>0</u><u>8</u><u>7</u><u>4</u><u>3</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u>.</u>

{ \sf{0.008743 \: moles \: of \: acid \: weigh \: 3.7066 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 3.7066}{0.008743}) \: g }} \\  = { \underline{423.95 \: g \approx424 \: grams}}

for the molar mass:

8 0
3 years ago
What is one main role of state governments?
mr Goodwill [35]
C.commanding the army the the navy would be right I think
7 0
2 years ago
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