Answer:
Chemotherapy drugs and other toxins are actively pumped out of cancer cells by transmembrane proteins.
Explanation:
Drugs inside the cell can be inactivated by oxidation and / or conjugation with glutathione, such as glutathione S-transferases, playing an important role in detoxification. However, conjugation is not enough for drug elimination. And this is where the GS-X pumps appear. Transporter proteins, such as Mrp protein, act as GS-X pumps. The PgP, Mrp and Bcrp proteins function as expulsion pumps, thus reducing the intracellular accumulation of drugs, causing resistance in cancer cells.
<span>Using a mixture of water, sand, and chemicals under high pressure to free tightly held oil and natural gas is known as Hy</span>draulic fracturing.
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This is a process commonly practiced in the United states where millions of gallons of water, sand, and chemicals are pumped underground. This is used to break apart the rock bed and release the gases that are deep in the ground.</span>
<span>Solids have molecules that are held tightly together in close bonds. (positive bonded to a negative) They can bend or vibrate but still stay bonded together closely. Solids have very little kinetic energy. </span>
<span>Liquids have molecules that are held in looser bonds. They move more freely and more randomly that in a solid. It is common for the bonds to be flexible enough to slide over each other. </span>
<span>Gasses have the loosest bond of any state of matter. The loose bonds allow the molecules to move freely and far apart. A gas has the greatest kinetic energy of any state of matter,</span>
603.040 has 5 significant figures in it I'm pretty sure
Answer:
Explanation:
<u><em>1. First determine the empirical formula.</em></u>
a) Base: 100 g of compound
mass atomic mass number of moles
g g/mol mol
C 26.06 12.011 26.06/12.011 = 2.17
H 13.13 1.008 13.13/1.008 = 13.03
N 60.81 14.007 60.81/14.007 = 4.34
b) Divide every number of moles by the smallest number: 2.17
mass number of moles proportion
C 2.17/2.17 1
H 13.03/2.17 6
N 4.34/2.17 2
c) Empirical formula
d) Mass of the empirical formula
<u><em>2. Molecular formula</em></u>
Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:
