What can be concluded about a tropical storm as it moves away from the equator?

An organism grew well on TSA plates, a bit slower on MM1 and not at all on MM1 without glucose. The results indicate that organi

Dafna11 [192]

Answer:

Can grow on MM1.

Explanation:

Organisms that can only grow in a media having specific nutrients included in it are called a fastidious organism, this implies that these organisms have specific nutrient requirements for their growth.
MM 1 represents the minimal media which has basic nutrients present in it, however as the fastidious organisms require some particular or complex nutrients for their growth they can not grow on the minimal media.
Therefore, since the organisms that are given in the question is able to grow on the minimal media MM1, this implies that it is not a fastidious organism.

5 0

3 years ago

What is the process by which arteries become hard and stiff as a result of too much pressure?.

erastovalidia [21]

Answer: atherosclerosis

Explanation:

8 0

2 years ago

Over 30 children younger than three years of age developed gastroenteritis after visiting a local water park. These cases repres

Flauer [41]

Answer:

No this is not an outbreak

Explanation:

No it cannot be classified as outbreak because an outbreak is when the number of affected individuals in an epidemic is much higher as compared to the estimated values. However, an epidemic is the one that affects the people around different countries of the globe.

This can be considered as endemic that is restricted to a certain set of people in a community

I would have studied pattern of movement of affected kids. The common pool to which all these kids visited can be the infectious one. Also one can test the pathogen in infected kinds, and look for similar pathogen in pool water through testing.

5 0

3 years ago

Which are true about forests? Choose all that apply. I. They are home to one-half of the world's people II. Traditional medicine

Alekssandra [29.7K]

Its IV. forests are habitat for two-thirds of terrestrials species....................

4 0

3 years ago

What fraction of offspring of the cross AaBb × AaBb would be homozygous for both the dominant alleles, assuming that they are on

Veseljchak [2.6K]

Answer:

A. 1/16

Explanation:

If we break the dihybrid cross of AaBb X AaBb into individual monohybrid crosses:

Aa X Aa :

A a

A AA Aa

a Aa aa

1/4 of the progeny will be homozygous for dominant allele (AA)

Similarly, in cross Bb X Bb 1/4 of the progeny will be homozygous for dominant allele (BB)

Hence, in cross AaBb X AaBb:

1/4 * 1/4 = 1/16 will be homozygous for both the dominant alleles.

6 0

3 years ago