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LekaFEV [45]
4 years ago
5

Solve. y = -3x + 6 y = 10x – 7

Mathematics
1 answer:
pickupchik [31]4 years ago
5 0
y = -3x + 6\\
y = 10x - 7\\\\
-3x+6=10x-7\\
-13x=-13\\
x=1\\\\
y=10\cdot1-7\\
y=3\\\\
\boxed{x=1,y=3}


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Sovle the system of linear equations by graphing y=2x-1 y=x+1
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Answer:

2x-1=x+1

2x-x=x

1+1=2

x=2

Knowing x's value, we substitute it with the equations

y=x+1

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Write an expression to represent multiplying the sum of 8 and 2 by 6.
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Answer:

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3 years ago
A: {71,73,79,83,87} B:{57,59,61,67}
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Answer:

\frac{3}{5}.

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

P(\text{Prime number from A})=\frac{4}{5}

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

P(\text{Prime number from B})=\frac{3}{4}

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}

P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}

P(\text{Prime number from A and B})=\frac{3}{5}

Therefore, the probability that both numbers are prime would be \frac{3}{5}.

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We know that the Pythagorean Theorem is a² + b² = c² and that the area of a square is l x w.

Firstly, we'll have to find the two measures of the triangle that correspond to the areas.

Since the figures are squares, we know that the length and width values must be the same.

We could square the numbers to find the side lengths, however we would have to square them again when substituting for the Pythagorean Theorem, so we can leave them as-is and adjust the equation accordingly.

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Next, we'll subtract our smaller value from our larger.

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Once again, we could find the square root of this number, but we'd just have to square it again to find the area of the square, so we can just simply write our answer as 11 units.

Therefore, the area of the square is 11 units!

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