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miss Akunina [59]
3 years ago
14

The area of a circle is 1256 square inches what is the length of its radius

Mathematics
1 answer:
Otrada [13]3 years ago
6 0
The formula of the area of a circle is : A= \pi R^2

You know that the area is 1256.

So : 1256= \pi R^2

Divide both sides by \pi :

\frac{1256}{\pi}=R^2

<span> take the square root of both sides in order to obtain r :

</span>\sqrt{ \frac{1256}{ \pi }}=R
20=R
<span>
In short, the answer would be 20 (i have rounded).

Hope this helps !

Photon
</span>

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Tiles with the letters A,B,C,D,E,F,G and H written on them are placed in a bag. Malik draws out on letter at random. Which state
dusya [7]

Using the probability concept, it is found that the correct statements are given as follows:

  • The number of possible outcomes is 8.
  • P(vowel)=1/4
  • P(vowel) + P(consonant) = 1.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are eight letters, two of which are vowels and six of which are consonants.

Hence:

  • P(vowel) = 2/8 = 1/4.
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E is one out eight letters, hence the probability is drawing the tile with E written on it is 1/8.

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juin [17]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u

Speed of current = v

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045

v = 0.5205

Now the time taken by the un powered raft to cover this distance

Because un powered raft travel with the speed of the current.

T = 192.12 hr

Therefore the  time taken by the un powered raft to cover this distance is

T = 192.12 hr

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3 years ago
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If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
bogdanovich [222]

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}

<em>We can now cross multiply and solve for CD:</em>

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


<em>Since the expression for CD is \frac{15x^2+16x+3.2}{2x+3} , we plug in x=2 into this expression to find value of CD:</em>

\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6

The correct answer is C

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If you wanted to calculate it, there it is:
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