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3 years ago

The difference of 7 and a number x is 10

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

The answer to the question

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What is this answer? 8(x-5)

Law Incorporation [45]

Answer:

8x-40

Step-by-step explanation:

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2 years ago

Read 2 more answers

Jacy buys 12 bottles of orange juice at the corner store for a total cost of $8.04. If each bottle costs the same amount , how m

weqwewe [10]

Answer:

$0.67

Step-by-step explanation:

8.04=12x

8.04=12x

12. 12

.67=x

6 0

3 years ago

What is the product of 3.6 x 4.2 How did you find it.

mixas84 [53]

Answer:

15.12

Step-by-step explanation:

3.6 x 4.2

first aline the decmials like you would regularly do to multiply.

Then multiply 2 x 6=12 and then 2 x 3=6 and put them down were you would already do noramly multiplying.

and then muliply 4x6=24 and 4x3=12 and do the same thing as you would do normaly and then add 72 and 144 to get 1512 and then count your decmail placing. which is 2 placeing in total which makes 1512 into 15.12

and now you done!

Example of how it should look...

3 . 6

× 4 . 2

+ 7 . 2

+ 1 4 4

= 1 5 1 2

6 0

3 years ago

Estimate the measure of the angle ? 85 70 235 310

alex41 [277]

Answer: 235 would be the estimate

5 0

3 years ago

A marble is selected at random from a jar containing 3 red marbles, 4 yellow marbles, and 6 green marbles. What is the probabi

alexgriva [62]

Answer: a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

a) the marble is red?

Probability of getting a red marble = $\dfrac{3}{13}$

b) the marble is not yellow?

Probability of not getting yellow = $\dfrac{3+6}{13}=\dfrac{9}{13}$

c) the marble is either red or green?

Probability of getting either red or green = P(red) + P(green) = $\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}$

d) the marble is neither red nor green?

Probability of getting neither red nor green = P(getting yellow) = $\dfrac{4}{13}$

Hence, a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

5 0

3 years ago