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loris [4]
3 years ago
12

Add

Mathematics
1 answer:
Alona [7]3 years ago
7 0
The correct answer is A
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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
3x-9x+6=20-3x+4x Please answer.
fomenos
I gotchu.
<span>3x-9x+6=20-3x+4x
Combine like terms.
-6x+6=20+x
Bring x over to the left side.
-x            -x
-7x+6=20
bring 6 to the right side.
     -6   -6
-7x=14
Divide -7 on both sides to isolate x.
x= -2

CHECK
</span><span>3x-9x+6=20-3x+4x
-6(-2)+6=20+(-2)
18=18 
ANSWER: x= -2</span>
6 0
3 years ago
Hello need help please with Divide rational and simplify
aliina [53]
Dividing fractions is the same as multiplying by its reciprocal so you can change the equation to this
\frac{ - 14 + 7x}{4}  \times  \frac{4}{4 - 2x}
And you can simplify by eliminating the fours and multiplying straight across
\frac{ - 14 + 7x}{4 - 2x}
You can pull out - 7 from the top and 2 from the bottom so you have this
\frac{ - 7(2  -  x)}{2(2 - x)}
And then you can cancel out to (2-x) to get an answer of
\frac{ - 7}{2}
5 0
3 years ago
Mai had $14.50. She spent $5.25 at the arcade. What is the exact amount of money<br> Mai has left?
patriot [66]

Answer:

nine dollars and 27 cents

Step-by-step explanation:

if u minus 14.50 minus 5.25 u get 9.27 9 dollars and 27 cents

Yw!

4 0
3 years ago
Read 2 more answers
9a^4+3a^2+21 please answer
SSSSS [86.1K]
What are you trying to find?
4 0
3 years ago
Read 2 more answers
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