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loris [4]
3 years ago
12

Add

Mathematics
1 answer:
Alona [7]3 years ago
7 0
The correct answer is A
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When the factors of a trinomial are (x+p) and (x-q) then the coeffcient of the x term in the trinomial is?
Tatiana [17]
The coefficient is:  "1" .
____________________________________________________
          Note:  There is an "<u>implied coefficient</u>" of "1"; since "1",  multiplied by any value, is equal to that exact same value; by convention, we eliminate the "1" as a coefficient.
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Further explanation:
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(x+p)(x−q) = x² − xq + px − pq ;
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(x+p)(x−q) =  {using "FOIL" → "First, Outer, Inner, and Last" terms}:
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<u>F</u>irst:    x*x = x² ;

<u>O</u>uter: x*(-q)= -xq ;

<u>I</u>nner:  p*x = px ;

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  (x + p)(x − q) = x² − xq + px − pq .
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4 0
3 years ago
Solve 2 – 4&lt;5. Graph the solution.<br> The solution is
Arturiano [62]

Answer:

x < 9

Step-by-step explanation:

Move the -4 over as if there was an equal sign so that x < 9

Take the arrow that looks like this "<---O" that is not filled in and put it on the number 9.

Let me know if this helps <3

6 0
2 years ago
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Suppose your SAT score is 1490. You look up the average SAT scores for
vivado [14]
The best in quality will probably be the 1470 but easiest to get i to is probably 1190 because if your sat score is way above their average they will think you are flaunting and deny your request
Plz mark as brainliest!
6 0
3 years ago
Can someone help me with these two for brilliant please
Yuri [45]

Answer:

its A

Step-by-step explanation:

7 0
2 years ago
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The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
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