There is an association because the value 0.15 is not similar to the value 0.55
For the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.
The conditions that satisfy whether there exists an association between conditional relative frequencies are:
1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.
2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.
For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
We can conclude that there is an association because the value 0.15 is not similar to the value 0.55
In the blank the answer is x axis
1.A 2.D 3.B These are the answers I think is the choice to your question.
Answer:
5
Step-by-step explanation:
To find B and C prime, you must multiply them by .25, or 1/4.
B' =
(-2 x .25),(1 x .25)
I did mine in fraction form, because it will prove to be more useful in future mathematics.
B' = (1/2 , 1/4)
Repeat the process with C.
C' =
(14 x .25),(17 x .25)
C' =
(7/2 , 17/4)
You only need to focus on B and C because you are finding the length of B'C'.
The formula for distance is the square root of x to the sub of 2 minus x to the sub of 1 squared minus y to the sub of 2 minus y to the sub of 1 square.
x2 - x1 = 7/2 - 1/2 = 6/2 = 3 squared = 9
y2 - y1 = 17/4 - 1/4 = 16/4 = 4 squared = 16
16 + 9 = 25
Square root of 25 is 5.
Therefore, the distance is 5.
9514 1404 393
Answer:
the marked choice is the correct one
Step-by-step explanation:
A suitable calculator or web app can reduce this matrix for you.
The solution is represented by the matrix ...
![\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-1\\0&0&1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%261%5C%5C0%261%260%26-1%5C%5C0%260%261%263%5Cend%7Barray%7D%5Cright%5D)
