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Ivanshal [37]
3 years ago
7

The daytime high temperature on the moon can reach 130°C. The nighttime low temperature can get as low as −110°C. What is the di

fference between the high and low temperatures?
Mathematics
1 answer:
maks197457 [2]3 years ago
7 0

Answer:

240

Step-by-step explanation:

remember that to get from positive to negative you have to go from positive to 0 then to negative .

however the easiest way of solving this is

add both the values , ignore the sign

130 + 110

the difference in the temperature is :

= 240 degrees

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To the nearest tenth, find the perimeter of ∆ABC with vertices A(-1,4), B(-2,1) and C(2,1).
swat32

First we need to find the length of each side of the triangle , and for that we need to use the distance formula, that is
d =\sqrt{(x_{2} -x_{1})^2 +(y_{2} -y_{1})^2}
AB = \sqrt{(1-4)^2 +(-2+1)^2}= \sqrt{10}
\sqrt{BC} = \sqrt{(1-1)^2 + (2+2)^2}=4
Perimeter is the sum of all sides.
Perimeter = AB + BC + AC = \sqrt{10}+4 +\sqrt{18}
Perimeter= 11.4

7 0
3 years ago
Joseph made a model rocket by attaching a cone
Lerok [7]

Answer:

Area = 270π inches squared. Volume = 550π inches cubed

Step-by-step explanation:

Surface Area:

Cylinder Area=2πrh+2πr^2= 180π+50π=230π inches squared.

Cone Area = πr(r+√(h^2+r^2)) = 5π(18) = 90π inches squared.

Total Area = 230π+90π = 320π inches squared.

Total Area - base = 320π-50π = 270π inches squared.

Volume:

Cylinder volume = πr^2h = 450π inches cubed

Cone volume = πr^2(h/3) = 100π inches cubed

Total Volume = 550π inches cubed

4 0
3 years ago
anthony uses 8 fluid ounces of lemon juice in one batch of lemonade. How many batches can he mane with 1 pint of lemon juice
ch4aika [34]

Answer:

Therefore, he can make 2 batches of lemonade with 1pint of lemon juice

8 0
2 years ago
What’s the volume of this
pav-90 [236]

Given:

The height of the cylinder = 12 in

The diameter of the base of the cylinder = 8 in.

To find:

The volume of the cylinder.

Solution:

The diameter of the base of the cylinder is 8 in. The radius is half of its diameter. So,

r=\dfrac{8}{2}

r=4

So, the radius of the base of the cylinder is 4 in.

The height of the cylinder, h = 12 in.

Base area of the cylinder is:

B=\pi r^2

Where, B is the base area and r is the radius.

B=\pi (4)^2

B=16\pi

So, the base area is 16\pi square inches.

The volume of the cylinder is:

V=\pi r^2h

V=Bh

Where, r is radius, h is height, B is base area.

Putting B=16\pi and h=12, we get

V=(16\pi )12

V=192\pi

So, the volume is 192\pi cubic inches.

Therefore, r=4\text{ in}, h=12\text{ in},B=16\pi \text{ in}^2,V=192\pi \text{ in}^3.

7 0
3 years ago
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. lim x→9 x − 9
luda_lava [24]

Without resorting to L'Hopitâl's rule,

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With the rule, we get the same result:

\displaystyle\lim_{x\to9}\frac{x-9}{x^2-81}=\lim_{x\to9}\frac1{2x}=\frac1{18}

8 0
3 years ago
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