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sasho [114]
3 years ago
5

On the triangle below which of the following best describes dh

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Can you please post a photo of the triangle!

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PLEASEE HEELLLP!!! I'LL GIVE BRAINLIEST!
Amanda [17]

Answer:

x = 3.25; y = 5.5; angle measures are (cw from bottom left): 96, 84, 96

Step-by-step explanation:

The two angles above the horizontal line form a linear pair, so they are supplementary. Their measures add to 180 deg. That let's you find the value of x.

28x - 7 + 24x + 18 = 180

52x + 11 = 180

52x = 169

x = 169/52

x = 3.25

Now use the lower left angle and the upper right angle. They are vertical angles, so they are congruent. That allows you to solve for y.

12y + 30 = 24x + 18

We know that x = 3.25.

12y + 30 = 24(3.25) + 18

12y + 30 = 78 + 18

12y = 66

y = 66/12

y = 5.5

I don't know what the problem is asking for since you don't show.

x = 3.25; y = 5.5; angle measures are (cw from bottom left): 96, 84, 96

8 0
3 years ago
Read 2 more answers
From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c
sergiy2304 [10]

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

5 0
3 years ago
Read 2 more answers
Help me please...<br> At least an explanation
In-s [12.5K]

Answer:

do u still need this question answeered?

Step-by-step explanation:

4 0
2 years ago
AABC has vertices at A(1, -9), B(8,0), and C(9,-8).
Rainbow [258]

Check the picture below.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0
2 years ago
2) WILL MARK BRAINLIEST + 10 POINTS! :)<br><br><br><br><br><br> HAPPY NEW YEAR!~!!!!!!!!!!!
Annette [7]
We can write the sequence out more fully, as we can see each time it is divided by 6.
60, 60/6, 60/6^2, 60/6^3, and so on.
Therefore we know the sequence can be written as u_n= \frac{60}{6^{n-1}}
You can think of this as a graph, i.e. y=60/6^(x-1)
As a result, as x tends to infinity, y tends to 0 (since it effectively becomes 60/infinity). Therefore the sequence converges toward zero.
5 0
3 years ago
Read 2 more answers
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