Question

A race car travels 99 m/s around a circular track of radius 52 m. What is the magnitude of the resultant force on the 1900 kg driver and his car if the car does not slip? Answer in units of kN.

Answer 1

Answer:

Force = 358.11 kN

Explanation:

Resultant force = Centripetal force.

$\texttt{Centripetal force, F = }\frac{mv^2}{r}$

Mass, m = 1900 kg

Velocity, v = 99 m/s

Radius, r = 52 m

Substituting

            $\texttt{Centripetal force, F = }\frac{mv^2}{r}\\\\F=\frac{1900\times 99^2}{52}\\\\F=358113.46N\\\\F=358.11kN$

Force = 358.11 kN