Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
Answer:
Explanation:
The acceleration of an object is given by Newton's second law:
where
F is the net force applied on the object
m is the mass of the object
For the book in the problem, we have:
is the mass
is the force applied
Substituting into the formula, we find the acceleration:
Answer:
3.03e-19 J
Explanation:
Use the formula E = hc/λ
Where:
h (Planck's constant) = 6.626e-34 J*s
c (speed of light, constant) = 3.00e8 m/s
λ (wavelength) = 656e-9 m
E = energy (in Joules)
E = (6.626e-34 * 3.00e8) / 656e-9 = 3.03018293e-19 = 3.03e-19 J
Friction but i may be wrong
