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Sergio039 [100]
2 years ago
5

Friction is a force in which two objects __________. A. Collide and move in one direction B. Are repelled from each other C. Sli

de against each other D. Are attracted from a distance Please select the best answer from the choices provided. A B C D.
Physics
1 answer:
Schach [20]2 years ago
6 0

Answer: (C) Slide against each other

Explanation:

Think about rubbing our palms together, and they get warm that right there is friction.

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What is the magnitude of the acceleration vector which causes a particle to move from velocity −5i−2j m/s to −6i+ 7j m/s in 8 se
shusha [124]

Answer:

Acceleration, a=\dfrac{1}{8}(-i+9j)\ m/s^2

Explanation:

Initial velocity of a particle in vector form, u = (-5i - 2j) m/s

Final velocity of particle in vector form, v = (-6i + 7j) m/s

Time taken, t = 8 seconds

We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{(-6i+7j)\ m/s-(-5i-2j)\ m/s}{8\ s}    

a=\dfrac{(-i+9j)}{8\ s}\ m/s^2    

or

a=\dfrac{1}{8}(-i+9j)\ m/s^2

Hence, the value of acceleration vector is solved.

4 0
3 years ago
Which of the following is NOT a characteristic of noble gases? *
statuscvo [17]

Answer:

solid at room temperature

Explanation:

they are unreactive

3 0
2 years ago
What is the resistance of a circuit with a voltage of 10 V and current of 5A is?
wolverine [178]

Resistance = (voltage) / (Current)

Resistance = (10 V) / (5 A)

Resistance = 2 ohms.

5 0
3 years ago
Read 2 more answers
An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
Svetlanka [38]

Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

Applying Gauss' law:

Electric Field E = Charge density/epsilon nought

Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

How far the electron would travel S =ut+ at^2/2 where u=0

S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

S=248.125mm

4 0
3 years ago
Which of these is exhibiting kinetic energy?1) a rock on a mountain ledge2) a space station orbiting Earth 3) a person sitting o
jarptica [38.1K]

The answer would be:

A space station orbiting Earth.

7 0
3 years ago
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