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AysviL [449]
3 years ago
6

ojectile is launched on the Earth with a certain ini- tial velocity and moves without air resistance. Another projectile is laun

ched with the same initial velocity on the Moon, where the acceleration due to gravity is one- sixth as large. How does the range of the projectile on the Moon compare with that of the projectile on the Earth? (a) It is one-sixth as large. (b) It is the same. (c) It is !6 times larger. (d) It is 6 times larger. (e) It is 36 times larger.
Physics
1 answer:
mafiozo [28]3 years ago
3 0
--vertical from ground to top--
v^2 = u^2 + 2as
with v= 0, a=g, s=u^2/(-2g)
g on the moon is 1/6
u is equal, then it goes 6 times higher on the moon.

v = u + at
with v= 0, a=g, t = u/(-g)
g on the moon is 1/6
u is equal, then it takes 6 times longer on the moon.

--horizontal--
s = vt , v is equal
t on the moon is 6 time longer
it moves 6 times farer on the moon
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Answer:

The total work on the ball is 36.25 Joules

Explanation:

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W_{net}=\Delta K = K_f -K_i (1)

With W net the total work, Kf the final kinetic energy and Ki the initial kinetic energy. We're going to use this principle to calculate the total work on the baseball by the force exerted by the bat.

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With m the mass of the object and v its velocity, knowing this we can use on:

W_{net}= \frac{mv_f^2 -mv_i^2}{2}=\frac{m(v_f^2 -v_i^2)}{2}

In our case vf is the velocity just after the hit and vi the velocity just before the hit. For an average baseball its mass is 145g that is 0.145 kg, then

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given terms are :

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