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1 answer:
These problems are fairly easy to work if you do what the instructions and hints tell you to do.
Quadrilateral WXZS is a rectangle of length 42 and width 11. Thus segment SY is 19-11 = 8 units, and WSY is a right triangle. By the Pythagorean theorem,
WY² = WS² +SY²
WY² = 42² +8² = 1764 +64 = 1828
WY = √1828 ≈ 42.76
The distance between the centers of the two circles is about 42.76.
Quadrilateral WXZS is a rectangle of length 42 and width 11. Thus segment SY is 19-11 = 8 units, and WSY is a right triangle. By the Pythagorean theorem,
WY² = WS² +SY²
WY² = 42² +8² = 1764 +64 = 1828
WY = √1828 ≈ 42.76
The distance between the centers of the two circles is about 42.76.
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Step-by-step explanation:
taking common (a-b)
so we get the answer
