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4 years ago

Name a supplementary angle

Mathematics

1 answer:

elena-s [515]4 years ago

7 0

Answer:

60° and 120° are supplementary angles. 93° and 87° are supplementary angles.

They are supplementary angles because they form an 180º angle together.

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The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that

Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital 2002 Inpatient Ratio 2002 Outpatient Ratio

1 68 54

2 100 75

3 71 53

4 74 56

5 100 74

6 83 71

Let $\mu_1$ = mean cost-to-charge ratio for outpatient care

$\mu_2$ = mean cost-to-charge ratio for impatient care.

SO, Null Hypothesis, $H_0$ : $\mu_1 \geq \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, $H_A$ : $\mu_1 < \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1_+_n_2_-_2$

where, $\bar X_1$ = sample mean cost-to-charge Outpatient Ratio = $\frac{\sum X_1}{n_1}$ = 63.83

$\bar X_2$ = sample mean cost-to-charge Impatient Ratio = $\frac{\sum X_2}{n_2}$ = 82.67

$s_1$ = sample standard deviation for Outpatient Ratio = $\sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} }$ = 10.53

$s_2$ = sample standard deviation for Impatient Ratio = $\sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} }$ = 14.33

$n_1$ = sample of hospital for outpatient care = 6

$n_2$ = sample of hospital for outpatient care = 6

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2} }{6+6-2} }$ = 12.574

So, the test statistics = $\frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6} } }$ ~ $t_1_0$

= -2.595

The value of t test statistics is -2.595.

Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0

4 years ago

Find H.C.F. of 144, 252 and 630

pentagon [3]

The HCF IS 18

HOPE THIS HELPS U

7 0

3 years ago

I need help with this pls very great full

dangina [55]

The answer to question 1 is here, I don't understand question 2 so I can't answer it.

5 0

2 years ago

Bag a contains 4 red and 3 blue tickets. bag b contains 3 red and 1 blue ticket. a bag is randomly selected by tossing a coin an

nikdorinn [45]

It's difficult to draw a tree diagram with this software.
Try to do it yourself & you will find the followings:

If A is selected (P(A) =1/2) we can get ether red (p(A & red)=4/7
so P(A∩red)= 1/2 x 4/7 = 4/14
Also we can get P(blue) = 3/7 & P(A∩blue) = 1/2 x 3/7 = 3/14

Same reasoning for B & you will get P(B∩read) 1/2 x 3/4 = 3/8
Also we can get P(B∩blue) = 1/2 x 1/4 = 1/8
Probability of blues is either 3/14 or 1/8
P(blue) = 3/8 +1/8 =19/56 = 0.339

6 0

3 years ago

8+(-3) full work thx If u can help

Kisachek [45]

Answer: 5

Step-by-step explanation:

8+(-3)

=8-3 ⇔ you don't need to change signs when it is positive(+) outside the parenthesis

=5 ⇔ subtraction

#CarryOnLearning

5 0

4 years ago

Read 2 more answers