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Rus_ich [418]
3 years ago
6

Xavier is driving home. He starts 250 miles from home and his car can travel 28 miles per gallon of gasoline he uses. Xavier sto

ps at a rest stop that is 100 miles from home. Let g be the amount or gas he has used at that point. Set up and solve an equation for how much gas Xavier used to get to the rest stop.
Mathematics
1 answer:
Leona [35]3 years ago
4 0

Answer:

For 100 miles he uses 3.571 gallons of gasoline.

In equation form it is y/x*100

Step-by-step explanation:

Unitary Method

He travels 28 miles per gallon of gasoline.

For 1 mile he uses  1/28 gallons

For 100 miles he uses 1/28 * 100= 100/28= 3.571 gallons of gasoline.

Let x be the miles and y be the gallons of gasoline used to travel x miles.

Then for 1 mile  the gallons of gasoline used will be y/ x gallons.

For 100 miles  the gallons of gasoline used will be y/x *100 gallons.

In equation form it is y/x*100 gallons for 100 miles where x is the number of miles and y is the amount of gallons.

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alukav5142 [94]

Refer to the attached image.

Given: m \angle A = 65^\circ and measure of exterior angle at C = 117^\circ.

We have to determine the measure of angle B and angle BCA.

By applying exterior angle property of the triangle which states:

"An exterior angle of a triangle is equal to the sum of the opposite interior angles".

So, exterior angle C = m \angle A + m \angle B

117^\circ = 65^\circ+ m \angle B

m \angle B = 52^\circ

Now, applying angle sum property in triangle ABC which states:

"The sum of all the angles of a triangle is 180 degrees".

m \angle A + m \angle B + m \angle BCA = 180^\circ

65^\circ + 52^\circ + m \angle BCA = 180^\circ

117^\circ + m \angle BCA = 180^\circ

m \angle BCA = 180^\circ - 117^\circ

m \angle BCA =63^\circ

Therefore, the measure of m \angle B = 52^\circ and m \angle BCA =63^\circ.

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3 years ago
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lutik1710 [3]

Answer:

540

Step-by-step explanation:

area of trapezium is b×h

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2 years ago
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Anastasy [175]
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The ratio is 1:3 therefore the answer is 1/3

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03. O preço a ser pago por uma corrida de táxi inclui uma parcela fixa, denominada bandeirada, e uma parcela que depende da dist
uranmaximum [27]

Answer: d) v = 3.20 + 1.50n.

Step-by-step explanation:

Let 'v' be the price to pay in a 'n' kilometer.

Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.

Flag costs = $ 3.20 and

Each kilometre run costs = $ 1.50

Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs +   (n)× (Each kilometre run costs )

⇒ v= 3.20 + 1.50n

Hence, the correct option is  d) v = 3.20 + 1.50n.

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