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<span>Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 17- 10 =7 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 19- 10 = 9
</span>
S = 2 + 6.8 + 2.45 = 11.25
<span>Zeff(Cl^-) = 17 – 11.25 = 5.75 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence </span>
<span>Zeff(K^+) = 19 - 11.25 = 7.75</span>
The new acceleration is 
Explanation:
We can answer this problem by applying Newton's second law, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
The equation can be rewritten as
In this problem, the initial acceleration is
Later:
- The net force is tripled: 
- The mass is halved: 
Therefore, the new acceleration is:
which means that the new acceleration is 6 times the original acceleration, therefore
Learn more about acceleration:
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If you walk at a pace of 2 miles per hour for 5 hours, you should have walked 10 miles. You would be 2 miles away from your base camp.
Yes I believe it would I think the answer is D
